Initial Value Linear system of DQ's

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SUMMARY

The discussion centers on solving a linear system of differential equations represented by the equations \(\frac{dv}{dt}=-34v-16w\) and \(\frac{dw}{dt}=80v+38w\) with initial conditions \(v(0)=-1\) and \(w(0)=-3\). The unique solution is expressed in terms of eigenvalues and eigenvectors, specifically \(v(t)= C_1 e^{-2t}+C_2 e^{6t}\) and \(w(t)= C_3 e^{-2t}+C_4 e^{6t}\). The eigenvalues identified are -2 and 6, with corresponding eigenvectors [-1,2] and [-2,5]. The constants \(C_1, C_2, C_3,\) and \(C_4\) were determined to be -11, 10, 22, and -25 respectively, based on the initial conditions.

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scorpius1782
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Homework Statement


The unique solution of the linear system of differential equations
##\frac{dv}{dt}=-34v+ -16w, v(0)=-1##
##\frac{dw}{dt}=80v+ 38w, w(0)=-3##
is: (enter the smaller of the eigenvalues first, and note that all entries here are integers)
##v(t)= C_1 e^{-2t}+C_2 e^{6t}##
##w(t)= C_3 e^{-2t}+C_4 e^{6t}##

I plugged in the exponential values since they're easy to get and not my problem.
Since I already know the answer to this practice problem:
##C_1=-11##
##C_2=10##
##C_3=22##
##C_4=-25##

Homework Equations





The Attempt at a Solution



I just can't figure out how they get the constants.

The eigenvalues are -2 and 6. And the eigenvectors are [-1,2] and [-2, 5]

I thought I was suppose to set the vectors in a matrix and set equal to the initial values but this doesn't work in anyway I've tried at all. I see that C1+C2=-1 and that the other two constants add up to -3 but I have no clue how they picked out those numbers. The example we did in class only had 1 constraint and was an annoyingly simple problem.

I've done everything I can think of to extract the method but am just missing the method. I'm sure it will be very simple. If anyone can please help me I'd appreciate it.
 
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Nevermind, solved it.
 

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