How Can You Linearize the Equation v=vw + (v0 - vw)e^-kt for Graphical Analysis?

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Homework Help Overview

The discussion revolves around the rearrangement of the equation v=vw + (v0 - vw)e^-kt, which describes the relationship between velocity, time, and constants in a physical chemistry context. The original poster seeks to linearize this equation for graphical analysis, specifically to identify how to plot the variables correctly and extract parameters from the graph.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to use the natural logarithm to simplify the equation for linearization but expresses difficulty in achieving a linear form. They consider plotting velocity against time and seek clarification on which quantities to use as ordinate and abscissa.

Discussion Status

Participants have offered guidance on rearranging the equation and suggested a potential form for plotting. There is an exploration of how to interpret the graph, including identifying the slope and intercept, but no explicit consensus has been reached on the final approach.

Contextual Notes

The original poster mentions their background in chemistry and challenges with physics concepts, which may influence their understanding of the mathematical aspects involved in the problem. There is also a note about the use of a semi-log plot, indicating a preference for graphical tools over manual calculations.

AlexLM
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Hi everyone!

I have an issue with my physical chemistry lab. They ask us to rearrange the fallowing equation

v=vw + (v0 - vw)e^-kt
where v is velocity and t is time, vw is a constant

They also ask which quantity would be plotted as ordinate and as absissa. We have to indicated the parameter of the slope and the intercept. Now once I have a equation I'll be able to find all those things but I can't seem to get to that equation.

I was thinking of plotting it for velocity and time. We also need to be able to figure out k from the graph

I tried for a while using the natural log of the function to lower the exponent and remove the e but I still can't seem to get a linear equation in which I'll be able to extract m and b.

As you can see I'm a chemistry student, not very good with anything physics related, and sorry for the broken English, it's my second language :)

Also sorry if this is in the wrong section, I'm new to this
 
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Welcome to PF!

Hi AlexLM! Welcome to PF! :smile:

Try writing it as v - vw = (v0 - vw)e-kt :wink:

(and btw, your English is fine :smile:)
 
Hi tiny-tim! Thanks a lot for the answer!

So basically if I graph for ln(v-vw)=ln(v0-vw) -kt I could use ln(v-vw) as my ordinate and t as my absissa. Then b would be ln(v0-vw) and the slope would be -k?

Does that make sense?
 
yup! :smile:

(oh, and it's "abscissa", from the Latin "abscindere" :wink:)
 
AlexLM said:
Hi tiny-tim! Thanks a lot for the answer!

So basically if I graph for ln(v-vw)=ln(v0-vw) -kt I could use ln(v-vw) as my ordinate and t as my absissa. Then b would be ln(v0-vw) and the slope would be -k?

Does that make sense?

If you do it on a semi-log plot, you don't actually have to calculate ln (v - v0). Your graphics package should have semi-log plot capabilities.
 

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