How do you graph y=3x-2 and identify points on the graph without using a prefix?

[bbg5000]

How do you...

Draw the graph of y=3x-2 on the grid. Identify at least two points on the graph by their coordinate pairs.

Anybody get that??

It's one of those x,y axis grid thingers. And there's a table under it with 8 columns and 2 rows. Kinda like..
______________________________________
X | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 |
Y | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 |

Something like that. Anybody help?

 

[bbg5000]

Also, I am asked to pick out which table represents a relation that is NOT a function.

A.
Input Value | +9 | 4 | 16 | 32
Output value|-18 | 8 | 32 | 64

B.
Input Value | 0 |1/-1|2/-2| 3
Output value| 0 | + 1 | +2 | 9

C.
Input Value | -2 | -1 | 0 | 1
Output value| +4 | +2 | 0| -2

D.
Input Value | 10 | 4 | 9 | 16
Output value| 0|2/-2|3/-3|4/-4

Any solutions?? I don't understand this stuff, especially at 0247hrs!

 

[matt grime]

a function cannot take one input and give two outputs, it's in the definition of function.

 

[HallsofIvy]

To answer the first question- Do the arithmetic!

Saying "y=3x-2" MEANS that if x is a certain number, then y is "3 times that number minus 2". You can make up a chart of "input value and output value", like you showed,
by choosing simple number for x (the "input value") and then calculating y (the "output value") according to that formula. The point about "identify at least 2 points" is that the graph of this is a straight line so, strictly speaking, it is determined by 2 points.

As to 2, As Matt Grime told you- a function cannot have two different "outputs" for the same "input". (They are trying to "fool" you a little in one of those by writing fractions that can be reduced. See what happens if you reduce them.)

 

[matt grime]

I read the / as an 'and' not a fraction, but the same thing applies.

 

[bbg5000]

So for this x, y chart thing, it'd go something like...

| x | y |
| 0 | -2|
| 2 | 4 |
| 4 | 7 |
| 5 | 13|

And then the second question is kinda like reversing it?? And the / was like and/or type thing. Sorry about that. So either one of those ones could be the one with a relation but not a function??

Thanks.​

 

[matt grime]

if the input is a and the output is b AND c, then it can't be a function by definition (where b and c are different).