How Do You Integrate Trigonometric Vectors with Variable Substitution?

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    Antiderivative
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Homework Help Overview

The discussion revolves around integrating a vector function involving trigonometric components, specifically focusing on the antiderivative and variable substitution techniques. The subject area includes calculus and vector calculus, particularly dealing with trigonometric identities and integration methods.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants explore different substitution methods for integrating the trigonometric vector components. Questions arise regarding the appropriateness of certain substitutions and the implications of using trigonometric identities, particularly concerning the cosine function.

Discussion Status

Some participants have suggested potential substitutions and expressed understanding of the integration process. There is an ongoing exploration of different variable choices to simplify the integration, with no explicit consensus on a single approach yet.

Contextual Notes

Participants note constraints related to the use of trigonometric substitutions and the specific forms of the vector components, which may affect the integration process. The original poster expresses confusion about the limitations of substitutions available for the cosine term.

afcwestwarrior
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3 sin ^2 t cos t (i) + 3 sin t cos^2 t (j) + 2 sin t cost (k)


I have to take the antiderivate for each Vector.

Then I have to evaluate it from pi/2 to o.

I'm confused because I can't use a trigonometric substitution.

Cosine is odd for the I vector but I can't substitute 1-sin^2 t in for it. Because it has to be cos^2 t
 
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for the i component, try a substitution since d/dt(sint)=cost, similar with the other two components.
 
I get it. If I make it like this, Sin (t) * Sin (t) * Cos (t) dt

t= sin (t)
dt = cos t)

it becomes t*t dt

then it becomes t^2 dt

and the integral of this is t^3 / 3
 
afcwestwarrior said:
I get it. If I make it like this, Sin (t) * Sin (t) * Cos (t) dt

t= sin (t)
dt = cos t)

it becomes t*t dt

then it becomes t^2 dt

and the integral of this is t^3 / 3

Use a different variable or you'll really confuse yourself.
u = sin(t), du = cos(t)dt

So the integrand sin2(t) cos(t) dt becomes u2 du
 

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