- #1
Haths
- 33
- 0
Basically. How would I even begin to go about doing the surface integral of a triangle bound by the co-ordinates;
(1,0,0)
(0,1,0)
(0,0,1)
This is part of a larger question to compute;
[tex]
\int \int \vec{F} \cdot d \vec{r}
[/tex]
Around the surface using stokes theorum, the scalar multiplier comes out as 2x+2y+2z so I'm not worried about that, but this last section of the question has dumfounded me completely. I might guess that I am being asked to develop a new co-ordinate referance point, and set of functions to describe it, but that appears like a hell of a lot of work for very little output.
Unless I am meant to cheat at this point and say; area of triangle 1/2 ab sin (theta) plug in sqrt(3) for a and b, to get an area of sqrt(3)/2 then multiply that by the scalar value to get a total of 3sqrt(3).
Yet that sounds very wrong.
Cheers,
Haths
(1,0,0)
(0,1,0)
(0,0,1)
This is part of a larger question to compute;
[tex]
\int \int \vec{F} \cdot d \vec{r}
[/tex]
Around the surface using stokes theorum, the scalar multiplier comes out as 2x+2y+2z so I'm not worried about that, but this last section of the question has dumfounded me completely. I might guess that I am being asked to develop a new co-ordinate referance point, and set of functions to describe it, but that appears like a hell of a lot of work for very little output.
Unless I am meant to cheat at this point and say; area of triangle 1/2 ab sin (theta) plug in sqrt(3) for a and b, to get an area of sqrt(3)/2 then multiply that by the scalar value to get a total of 3sqrt(3).
Yet that sounds very wrong.
Cheers,
Haths
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