- #1

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Basically. How would I even begin to go about doing the surface integral of a triangle bound by the co-ordinates;

(1,0,0)

(0,1,0)

(0,0,1)

This is part of a larger question to compute;

[tex]

\int \int \vec{F} \cdot d \vec{r}

[/tex]

Around the surface using stokes theorum, the scalar multiplier comes out as 2x+2y+2z so I'm not worried about that, but this last section of the question has dumfounded me completly. I might guess that I am being asked to develop a new co-ordinate referance point, and set of functions to describe it, but that appears like a hell of a lot of work for very little output.

Unless I am meant to cheat at this point and say; area of triangle 1/2 ab sin (theta) plug in sqrt(3) for a and b, to get an area of sqrt(3)/2 then multiply that by the scalar value to get a total of 3sqrt(3).

Yet that sounds very wrong.

Cheers,

Haths

(1,0,0)

(0,1,0)

(0,0,1)

This is part of a larger question to compute;

[tex]

\int \int \vec{F} \cdot d \vec{r}

[/tex]

Around the surface using stokes theorum, the scalar multiplier comes out as 2x+2y+2z so I'm not worried about that, but this last section of the question has dumfounded me completly. I might guess that I am being asked to develop a new co-ordinate referance point, and set of functions to describe it, but that appears like a hell of a lot of work for very little output.

Unless I am meant to cheat at this point and say; area of triangle 1/2 ab sin (theta) plug in sqrt(3) for a and b, to get an area of sqrt(3)/2 then multiply that by the scalar value to get a total of 3sqrt(3).

Yet that sounds very wrong.

Cheers,

Haths

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