Calculating Mass of Triangle Surface Given Density 4xz

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SUMMARY

The discussion focuses on calculating the mass of a triangular surface defined by vertices (2,0,0), (0,2,0), and (0,0,1) with a variable density of 4xz. The key steps involve using integration and the cross product to derive the surface area element, dS = sqrt(3/2) dA. To find the mass, the density must be expressed in terms of x and y by substituting z from the plane equation. The user seeks clarification on how to derive the expression (4x – 2x^2 – 2xy) from the density function.

PREREQUISITES
  • Understanding of surface integrals in multivariable calculus
  • Familiarity with the cross product and its application in finding normal vectors
  • Knowledge of plane equations and how to express variables in terms of others
  • Basic integration techniques for calculating mass from density functions
NEXT STEPS
  • Study the derivation of surface area elements in surface integrals
  • Learn how to express variables in terms of others using plane equations
  • Explore the application of variable density in mass calculations
  • Review examples of integrating functions over triangular surfaces
USEFUL FOR

Students in calculus or physics courses, particularly those studying multivariable calculus and surface integrals, as well as educators looking for examples of variable density applications in mass calculations.

s3a
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Homework Statement


Find the mass of the surface of the triangle with vertices (2,0,0), (0,2,0) and (0,0,1) if the density is 4xz. The solution is attached as TheSolution.jpg.

Homework Equations


Integration. Cross product. Plane equation: a(x-x_0) + b(y-y_0) + c(z-z_0) = 0 where <a,b,c> = n (vector that is normal to the plane) and where (x_0,y_0,z_0) is any arbitrarily chosen vertice.

The Attempt at a Solution


Having watched (1) and read (2),:

(1)
(2) http://www.math.oregonstate.edu/hom...usQuestStudyGuides/vcalc/surfint/surfint.html

I have successfully reached the dS = sqrt(3/2) dA step and for the next step, I'm supposed to multiply the density by the surface area in order to get the mass of the surface but, I just don't see how I'm supposed to get the (4x – 2x^2 – 2xy) part nor do I see how the variable density, 4xz, relates to that; I'm not sure that it should relate but I feel it should.

Could someone please help me understand the step I am stuck on?

Any help would be greatly appreciated!
Thanks in advance!
 

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s3a said:

Homework Statement


Find the mass of the surface of the triangle with vertices (2,0,0), (0,2,0) and (0,0,1) if the density is 4xz. The solution is attached as TheSolution.jpg.

Homework Equations


Integration. Cross product. Plane equation: a(x-x_0) + b(y-y_0) + c(z-z_0) = 0 where <a,b,c> = n (vector that is normal to the plane) and where (x_0,y_0,z_0) is any arbitrarily chosen vertice.

The Attempt at a Solution


Having watched (1) and read (2),:

(1)
(2) http://www.math.oregonstate.edu/hom...usQuestStudyGuides/vcalc/surfint/surfint.html

I have successfully reached the dS = sqrt(3/2) dA step and for the next step, I'm supposed to multiply the density by the surface area in order to get the mass of the surface but, I just don't see how I'm supposed to get the (4x – 2x^2 – 2xy) part nor do I see how the variable density, 4xz, relates to that; I'm not sure that it should relate but I feel it should.

Could someone please help me understand the step I am stuck on?

Any help would be greatly appreciated!
Thanks in advance!


You have expressed the plane as z in terms of x and y. In the integral, the z in the density formula 4xz must be replaced by its value in terms of x and y on the plane.
 
Last edited by a moderator:
Thanks!
 

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