How Do You Prove and Analyze RC Circuit Formulas?

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SUMMARY

This discussion focuses on proving and analyzing formulas related to RC circuits in a physics lab context. The key equations involved are dQ/dt = -Q/RC, Q = (Qo)e^(-t/RC), and Q(t) = CE[1 - e^(-t/RC)]. The participants confirm that equation 1b is the solution to the differential equation 1a, and they emphasize the need to differentiate Q(t) to find the current. Additionally, they highlight the importance of dimensional analysis for the time constant RC.

PREREQUISITES
  • Understanding of differential equations, specifically in the context of RC circuits.
  • Familiarity with SI derived units, particularly resistance (R) and capacitance (C).
  • Knowledge of exponential functions and their derivatives.
  • Basic skills in dimensional analysis.
NEXT STEPS
  • Learn how to differentiate exponential functions in the context of physics problems.
  • Study the concept of time constants in RC circuits and their significance.
  • Explore dimensional analysis techniques for verifying physical equations.
  • Investigate the relationship between charge, current, and voltage in RC circuits.
USEFUL FOR

Students in introductory physics courses, educators teaching circuit theory, and anyone interested in understanding the mathematical foundations of RC circuits.

dmitriylm
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Homework Statement



I'm doing a physics lab and have a question about RC circuits. I'm given four formulas:

1a) dQ/dt = -Q/RC
1b) Q = (Qo)e^(-t/RC)
1c) E - RI - Q/C = 0 ---> R(dQ/dt) + Q/C - E = 0
1d) Q(t) = CE[1 - e^(-t/RC)]

I am told that 1b is the solution to 1a and 1d is the solution to 1c.

a) Equation 1b is called "the solution" to the differential question, 1a because when you plug in Q(t) (from 1b) into equation 1a, the resulting left side of the equation is equal to the right side. Prove that 1b is the solution by plugging it into equation 1a.

b) Demonstrate that RC has the dimensions of time.

c) Plug 1d into 1c and show that it works, as you did in question a.

d) Differentiate Q(t) to obtain an expression for the current.

Homework Equations


1a) dQ/dt = -Q/RC
1b) Q = (Qo)e^(-t/RC)
1c) E - RI - Q/C = 0 ---> R(dQ/dt) + Q/C - E = 0
1d) Q(t) = CE[1 - e^(-t/RC)]


The Attempt at a Solution



Not quite sure what should be done to make this work. Can anyone please explain this for me?
 
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This is really more of an Introductory Physics type question.

a) they are telling you exactly how to proceed--plug eq. 1b into eq. 1a. (you'll need to be able to differentiate eq. 1b with respect to time).
b) you are being asked to do a dimensional analysis of RC. Hint: R and C are SI "derived units" (based on SI "base units").
c) same as a)
d) you'll need to differentiate eq. 1d with respect to time, which you already did if you did part c).
 

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