How Do You Prove This Inequality Using Induction?

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Homework Help Overview

The discussion revolves around proving an inequality involving square roots and natural numbers, specifically the inequality \( 2( \sqrt{n+1} - \sqrt{n} ) < \frac{1}{ \sqrt{n}} < 2( \sqrt{n} - \sqrt{n-1}) \) for \( n \in \mathbb{N} \). Participants are exploring methods of proof, including mathematical induction and direct proof approaches.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Some participants discuss the potential for using mathematical induction, expressing uncertainty about which equations can be assumed true for the induction step. Others suggest that a direct proof may be more straightforward and propose manipulating the inequalities or considering approximations related to integrals.

Discussion Status

The discussion is active, with various perspectives on the best approach to the problem. Some participants have provided alternative methods, such as direct proofs, while others are questioning the necessity of induction. There is no explicit consensus on the preferred method, but several lines of reasoning are being explored.

Contextual Notes

Participants are grappling with the assumptions necessary for induction and the implications of the inequalities as \( n \) approaches larger values. There is also a mention of LaTeX formatting issues that may affect clarity in the discussion.

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Homework Statement


Show that [tex]2( \sqrt{n+1} - \sqrt{n} ) < \frac{1}{ \sqrt{n}} < 2( \sqrt{n} - \sqrt{n-1}), n \in N[/tex]

2. The attempt at a solution

this works for n=1, but I'm entirely at a loss when trying to figure out which equations i can assume to be 'obviously' true (for the sake of the induction step), and what cannot be assumed..
All sides of the inequality eventually become 0, and while it seems fairly obvious to me that they all do it at an incrementally slower pace than the preceding one, I'm not sure what to make of this mathematically, or how to mold it into an equation expressing that.. can anyone lend a hand?

@radou: sorry, took a few mins to figure out what i'd done wrong
 
Last edited:
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You may want to correct your LaTeX code.
 
Unless the question says "prove by induction", a direct proof is easy.

Take each inequality separately, multiply both sides by \root n, and it should be fairly obvious what to do after that.

Another direct proof: think about approximations to
[tex]\int x^{-1/2} \, dx[/tex]
 
Last edited:
I can't possibly see how induction could do it.

Daniel.
 
indeed, a direct proof is much much easier than induction... the inequalities are equivalent to:
[tex]\sqrt{n+1}-\sqrt{n}>0[/tex]
 
I suppose you could argue that a direct proof IS a proof by induction.

You say "assume the result is true for n = k-1", then show it is true for n = k ... even though you never actually used the assumption :wink:
 
bah. i feel like I'm really not very bright here, but why is the difference between the sqrts of 2 successive natural numbers always < .5 ?
 
multiply out:

[tex](\sqrt{n+1}-\sqrt{n}) \frac{\sqrt{n+1}+\sqrt{n}}{\sqrt{n+1}+\sqrt{n}}[/tex]
 

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