How Do You Simplify 12/4 in an Indefinite Integral?

In summary, the conversation discusses how to handle the fraction ##\frac{1}{12}\,\cdot\, \frac{1}{\frac{5}{4}} = \frac{\frac{1}{12}}{\frac{5}{4}}## and whether it is a composite or mixed fraction. The conversation also addresses a mathjax typo and clarifies the presence of a ##u-##term. The final summary explains the steps to simplify the fraction.
  • #1
NickTesla
29
3
upload_2016-10-12_22-4-35.png


doubt in this fraction in here
upload_2016-10-12_22-1-36.png
Because he, simplify 12 with 4 ?? do not understand!
someone could make another example ,with fraction ! Thank you!
 
Physics news on Phys.org
  • #2
Do you know how to handle ##\frac{1}{12}\,\cdot\, \frac{1}{\frac{5}{4}} = \frac{\frac{1}{12}}{\frac{5}{4}}##?
 
  • Like
Likes NickTesla
  • #3
You have a mathjax typo @fresh_42 ...
 
  • #4
jim mcnamara said:
You have a mathjax typo @fresh_42 ...
Yeah, failed attempt to enlarge the numbers.
Thanks, anyway!
 
  • Like
Likes NickTesla
  • #5
fresh_42 said:
Do you know how to handle ##\frac{1}{12}\,\cdot\, \frac{1}{\frac{5}{4}} = \frac{\frac{1}{12}}{\frac{5}{4}}##?

fresh 42 Thank you, is composite or Mixed
fraction ?? the account of this? u ^ 5/4, you wrote the same number 1 or u = 1 ?? I then replace u by 1 correct ??
 
  • #6
NickTesla said:
fresh 42 Thank you, is composite or Mixed
fraction ?? the account of this? u ^ 5/4, you wrote the same number 1 or u = 1 ?? I then replace u by 1 correct ??
No, I left out the ##u-##term. With it, it reads

##-\frac{1}{12}\,\cdot \, \frac{u^{5/4}}{\frac{5}{4}} = -\frac{\frac{1}{12}}{\frac{5}{4}} \,\cdot \, u^{5/4} = -\frac{1}{12} \, \cdot \, \frac{4}{5} \,\cdot \, u^{5/4} = -\frac{1\,\cdot\,4}{12 \,\cdot\, 5}\,\cdot\, u^{5/4} =-\frac{4}{60}\,\cdot\, u^{5/4} = -\frac{1}{15}\,\cdot\, u^{5/4}##

Look at the fractions here and how they are divided!
 
  • Like
Likes NickTesla
  • #7
Thank you, now easier!
 

FAQ: How Do You Simplify 12/4 in an Indefinite Integral?

What is an indefinite integral?

An indefinite integral is the reverse process of differentiation. It gives the function whose derivative is the original function. It is represented by the ∫ symbol and has no upper or lower limits.

How is an indefinite integral different from a definite integral?

A definite integral has upper and lower limits, while an indefinite integral does not. A definite integral gives a specific numerical value, while an indefinite integral gives a function.

What is the process for finding an indefinite integral?

To find an indefinite integral, you must use integration techniques such as substitution, integration by parts, or partial fractions. These techniques involve manipulating the function and applying rules of integration.

What is the relationship between derivatives and indefinite integrals?

The derivative of a function is the slope of the tangent line at a given point, while the indefinite integral gives the original function. This means that the derivative and indefinite integral are inverse operations of each other.

Why is it important to understand indefinite integrals?

Indefinite integrals are important in various fields of science, such as physics and engineering, as they are used to find the area under a curve and to solve differential equations. They also help in understanding the behavior of functions and their relationships with each other.

Similar threads

Replies
9
Views
2K
Replies
6
Views
2K
Replies
20
Views
4K
Replies
12
Views
3K
Replies
6
Views
2K
Back
Top