B How Do You Simplify 12/4 in an Indefinite Integral?

[NickTesla]

doubt in this fraction in here

Because he, simplify 12 with 4 ?? do not understand!
someone could make another example ,with fraction ! Thank you!

 

[fresh_42]

Do you know how to handle $\frac{1}{12}\,\cdot\, \frac{1}{\frac{5}{4}} = \frac{\frac{1}{12}}{\frac{5}{4}}$?

 

[jim mcnamara]

You have a mathjax typo @fresh_42 ...

 

[fresh_42]

You have a mathjax typo @fresh_42 ...

Yeah, failed attempt to enlarge the numbers.
Thanks, anyway!

 

[NickTesla]

Do you know how to handle $\frac{1}{12}\,\cdot\, \frac{1}{\frac{5}{4}} = \frac{\frac{1}{12}}{\frac{5}{4}}$?

fresh 42 Thank you, is composite or Mixed
fraction ?? the account of this? u ^ 5/4, you wrote the same number 1 or u = 1 ?? I then replace u by 1 correct ??

 

[fresh_42]

fresh 42 Thank you, is composite or Mixed
fraction ?? the account of this? u ^ 5/4, you wrote the same number 1 or u = 1 ?? I then replace u by 1 correct ??

No, I left out the $u-$term. With it, it reads

$-\frac{1}{12}\,\cdot \, \frac{u^{5/4}}{\frac{5}{4}} = -\frac{\frac{1}{12}}{\frac{5}{4}} \,\cdot \, u^{5/4} = -\frac{1}{12} \, \cdot \, \frac{4}{5} \,\cdot \, u^{5/4} = -\frac{1\,\cdot\,4}{12 \,\cdot\, 5}\,\cdot\, u^{5/4} =-\frac{4}{60}\,\cdot\, u^{5/4} = -\frac{1}{15}\,\cdot\, u^{5/4}$

Look at the fractions here and how they are divided!

 

[NickTesla]

Thank you, now easier!