How Do You Simplify Complex Algebraic Fractions?

AI Thread Summary
The discussion focuses on simplifying the algebraic expression 1/2700 + 1/(3930n^2) + 10^{-5}. Participants clarify the correct method for combining these fractions, emphasizing the importance of treating 10^{-5} properly in the context of fractions. There is confusion regarding the representation of 10^{-5} as 1/10^5, which leads to incorrect simplifications. The correct approach aligns with the formula for adding fractions, confirming that the book's method is accurate. Overall, the conversation highlights the significance of careful fraction manipulation in algebra.
Jason-Li
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Homework Statement
Working through some fractions in loop-gain of an oscillator and stuck when comparing my answer to the learning materials...
Relevant Equations
algebra & fractions
So my final equation is:

##\frac {1} {2700} + \frac {1} {3930n^2} + 10^{-5}##

I need to boil this down, the learning materials has the following working, but I can't seem to get it
$$\frac {1} {2700} + \frac {1} {3930n^2} + 10^{-5}$$

$$\frac {3930n^2+2700+2700*3930n^2*10^{-5}} {(2700*3930n^2)}$$

But I have the following:

$$\frac {(3930n^2+2700)*10^{-5}+2700*3930n^2*10^{-5}} {(2700*3930n^2)}$$

Not sure why I have the extra 10^{-5} or how to get rid of it?

Unless the following makes mathematical sense? by making 10^{-5} = 1/ 10^{5}

$$\frac {(3930n^2+2700)*10^{5}+2700*3930n^2} {(2700*3930n^2)*10^5}$$
$$\frac {(3930n^2+2700)+2700*3930n^2*10^{-5}} {(2700*3930n^2)}$$

But the problem is $$\frac {(3930n^2+2700)*10^{5}+2700*3930n^2} {(2700*3930n^2)*10^5} ≠ \frac {(3930n^2+2700)+2700*3930n^2*10^{-5}} {(2700*3930n^2)}$$
 
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In general $$\frac 1 a + \frac 1 b + c = \frac{b + a + abc}{ab}$$
So, the book is correct.

I think you are confusing ##10^{-5}## with ##\frac 1 {10^5}## in terms of how you treat it as a fraction.
 
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PS you can always set ##n = 1## and put each expression into a calculator or spreadsheet. You'll see that your expression is incorrect.
 
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PeroK said:
In general $$\frac 1 a + \frac 1 b + c = \frac{b + a + abc}{ab}$$
So, the book is correct.

I think you are confusing ##10^{-5}## with ##\frac 1 {10^5}## in terms of how you treat it as a fraction.

PeroK,

I should've simplified it down first like you have e.g. abc...

Thanks again!
 
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PeroK said:
I think you are confusing ##10^{-5}## with ##\frac 1 {10^5}## in terms of how you treat it as a fraction.
That would be fine, since they are equal, as long as it was done correctly.
 
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Jason-Li said:
So my final equation is: ##\frac {1} {2700} + \frac {1} {3930n^2} + 10^{-5}##
Nit: That's not an equation. An equation is a statement about the equality of two expressions. An equation will always include at least one = symbol.
 
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Mark44 said:
Nit: That's not an equation. An equation is a statement about the equality of two expressions. An equation will always include at least one = symbol.
And a good way of remembering is looking at the first 4 letters of the word : Edit :equa(l)(ity)
 
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WWGD said:
And a good way of remembering is lo9king at the first 4 letters of the word : aqua(l)(ity)
aqua?
 
Mark44 said:
aqua?
Auto (in)correct strikes again. Let me edit.
 
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