How Do You Simplify Complex Algebraic Fractions?

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SUMMARY

The discussion focuses on simplifying the algebraic expression $$\frac {1} {2700} + \frac {1} {3930n^2} + 10^{-5}$$. Participants clarify the correct approach to combining these fractions, emphasizing the formula $$\frac 1 a + \frac 1 b + c = \frac{b + a + abc}{ab}$$ as a foundational principle. A common point of confusion arises from treating $$10^{-5}$$ as a fraction, which is equivalent to $$\frac{1}{10^5}$$. The consensus is that the original equation can be simplified correctly by following established algebraic rules.

PREREQUISITES
  • Understanding of algebraic fractions
  • Familiarity with the concept of least common denominators
  • Knowledge of exponent rules, particularly negative exponents
  • Ability to manipulate algebraic expressions
NEXT STEPS
  • Study the properties of algebraic fractions and their simplification techniques
  • Learn about the application of least common denominators in complex fractions
  • Explore exponent rules, focusing on negative exponents and their implications
  • Practice simplifying various algebraic expressions using calculators or spreadsheets
USEFUL FOR

Students, educators, and anyone looking to enhance their understanding of algebraic simplification techniques, particularly in the context of complex fractions.

Jason-Li
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Homework Statement
Working through some fractions in loop-gain of an oscillator and stuck when comparing my answer to the learning materials...
Relevant Equations
algebra & fractions
So my final equation is:

##\frac {1} {2700} + \frac {1} {3930n^2} + 10^{-5}##

I need to boil this down, the learning materials has the following working, but I can't seem to get it
$$\frac {1} {2700} + \frac {1} {3930n^2} + 10^{-5}$$

$$\frac {3930n^2+2700+2700*3930n^2*10^{-5}} {(2700*3930n^2)}$$

But I have the following:

$$\frac {(3930n^2+2700)*10^{-5}+2700*3930n^2*10^{-5}} {(2700*3930n^2)}$$

Not sure why I have the extra 10^{-5} or how to get rid of it?

Unless the following makes mathematical sense? by making 10^{-5} = 1/ 10^{5}

$$\frac {(3930n^2+2700)*10^{5}+2700*3930n^2} {(2700*3930n^2)*10^5}$$
$$\frac {(3930n^2+2700)+2700*3930n^2*10^{-5}} {(2700*3930n^2)}$$

But the problem is $$\frac {(3930n^2+2700)*10^{5}+2700*3930n^2} {(2700*3930n^2)*10^5} ≠ \frac {(3930n^2+2700)+2700*3930n^2*10^{-5}} {(2700*3930n^2)}$$
 
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In general $$\frac 1 a + \frac 1 b + c = \frac{b + a + abc}{ab}$$
So, the book is correct.

I think you are confusing ##10^{-5}## with ##\frac 1 {10^5}## in terms of how you treat it as a fraction.
 
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PS you can always set ##n = 1## and put each expression into a calculator or spreadsheet. You'll see that your expression is incorrect.
 
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PeroK said:
In general $$\frac 1 a + \frac 1 b + c = \frac{b + a + abc}{ab}$$
So, the book is correct.

I think you are confusing ##10^{-5}## with ##\frac 1 {10^5}## in terms of how you treat it as a fraction.

PeroK,

I should've simplified it down first like you have e.g. abc...

Thanks again!
 
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PeroK said:
I think you are confusing ##10^{-5}## with ##\frac 1 {10^5}## in terms of how you treat it as a fraction.
That would be fine, since they are equal, as long as it was done correctly.
 
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Jason-Li said:
So my final equation is: ##\frac {1} {2700} + \frac {1} {3930n^2} + 10^{-5}##
Nit: That's not an equation. An equation is a statement about the equality of two expressions. An equation will always include at least one = symbol.
 
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Mark44 said:
Nit: That's not an equation. An equation is a statement about the equality of two expressions. An equation will always include at least one = symbol.
And a good way of remembering is looking at the first 4 letters of the word : Edit :equa(l)(ity)
 
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WWGD said:
And a good way of remembering is lo9king at the first 4 letters of the word : aqua(l)(ity)
aqua?
 
Mark44 said:
aqua?
Auto (in)correct strikes again. Let me edit.
 

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