How Do You Solve (2x-y+1)dx+(x+y)dy=0 Using a Linear Transformation?

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To solve the differential equation (2x-y+1)dx+(x+y)dy=0 using a linear transformation, the first step involves finding the intersection of the lines y=2x+1 and y=-x, which helps in simplifying the equation. A transformation is then applied by substituting new variables (u, v) to remove constant terms, resulting in a homogeneous equation. The discussion highlights the importance of understanding the difference between linear and affine transformations, with suggestions for various methods to analyze the resulting equations, including parametric forms and polar coordinates. Ultimately, the conversation emphasizes the complexity of the problem and the different approaches to finding a solution.
  • #31
Yes, you're right~
There's lots of different approaches to a question~
It's just that...
You guys are amazing!
I'd never of thought to come up with those ideas~
It makes me want to start jumping into mathematics books and brush up on my math~
 
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  • #32
After homogenizing, the generic solution to the polar form looks like the product of these four terms to various powers: (if I haven't made a mistake)

(A + B tan θ + C tan² θ)
exp(arctan(D tan θ + E))
sec θ
exp(θ)

times some constant.

Sigh, not all that enlightening. :frown: Everything except the "some constant" depend on the coefficients in the original problem.
 

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