How Do You Solve a Combination Lens Problem in Optics?

  • Thread starter Thread starter Darth Frodo
  • Start date Start date
  • Tags Tags
    Combination Lens
Click For Summary
SUMMARY

The discussion focuses on solving a combination lens problem involving a convex lens with a focal length of 80 mm and a concave lens with a focal length of 25 mm. The object is placed 400 mm in front of the convex lens, resulting in an image formation at 100 mm to the right of the convex lens. The subsequent image from the convex lens serves as the object for the concave lens, which is positioned 80 mm behind the convex lens. The final image is calculated to be at 100 mm from the concave lens, confirming the correctness of the calculations provided.

PREREQUISITES
  • Understanding of lens formulas, specifically the thin lens equation
  • Knowledge of focal lengths and their impact on image formation
  • Familiarity with the concepts of object distance (U) and image distance (V)
  • Basic principles of optics, including the behavior of convex and concave lenses
NEXT STEPS
  • Study the thin lens equation in detail, focusing on practical applications
  • Learn about ray diagrams for both convex and concave lenses
  • Explore the concept of magnification in lens systems
  • Investigate more complex lens combinations and their applications in optical devices
USEFUL FOR

Students studying optics, physics educators, and anyone interested in understanding lens systems and image formation in optical devices.

Darth Frodo
Messages
211
Reaction score
1

Homework Statement



An object is placed 400 mm in front of a convex lens of focal length 80 mm. Find the position of the image formed. State the nature of this image.

A second concave lens of focal length 25 mm is placed 80 mm behind the first convex lens. Find the position of the final image formed and state its nature.

The Attempt at a Solution



\frac{1}{U} + \frac{1}{V} = \frac{1}{F}

\frac{1}{V} = \frac{1}{80} - \frac{1}{400}

V = 100 mm



So the Image from lens one forms 100 mm to the right of lens one. BUT, lens 2 is only 80 mm to the right of lens 1. I don't know what to do here since no image has been formed to create a new object for lens 2.

Any help?
 
Physics news on Phys.org
Which means the Object´s image will appear to the right (or behind) of the concave lense.
80-100= -20
U=-20 solve for V
 
\frac{1}{-20} + \frac{1}{V_{2}} = \frac{1}{F}

\frac{1}{V_{2}} = \frac{1}{20} - \frac{1}{25} = \frac{1}{100}

V = 100
 
Is this correct?
 

Similar threads

  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 15 ·
Replies
15
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K
Replies
1
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 16 ·
Replies
16
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K