The discussion revolves around solving the exponential inequality \(2^x + 2^{4-x} > 17\), which involves manipulating expressions with different bases of exponents.
Some participants have made progress in their attempts, with one indicating they have solved the inequality correctly. However, there is still a lack of clarity on the specific steps taken and the final values for \(x\). The discussion remains open with various interpretations being explored.
There is a focus on understanding the manipulation of the inequality and the implications of different approaches, with participants questioning the assumptions made during the problem-solving process.
Let u = 2x .scientifico said:Homework Statement
2^x + 2^(4-x) > 17
2.The attempt at a solution
I factorized for 2^(-x) so I have 2^(-x) * (16 + 2^(2x)) > 17 but I don't know what to do after... could you help me ?
thanks
What did you get when you solved for x ?scientifico said:Thanks I figured it out and solved correctly.
(u^2 - 17u +16)/u > 0