How Do You Solve Complex Circuit Problems?

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SUMMARY

The forum discussion focuses on solving complex circuit problems involving resistors, specifically calculating the current and potential difference across a 1.3 Ω resistor and a 10.0 Ω resistor. The key equations used include Ohm's Law (V = IR) and the formula for equivalent resistance in parallel circuits (1/Req = 1/R1 + 1/R2 + ...). The equivalent resistance was calculated to be approximately 6.157 Ω, leading to a total current of about 2.92 A. The discussion emphasizes the importance of correctly identifying parallel and series resistances to solve for individual currents in the circuit.

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  • Understanding of Ohm's Law (V = IR)
  • Knowledge of calculating equivalent resistance in parallel circuits
  • Familiarity with basic circuit analysis techniques
  • Ability to interpret circuit diagrams
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Homework Statement


Consider the circuit in the figure.
Circuits 001.jpg

Find the current in the 1.3 Ω resistor. Answer in units of A.
Find the potential difference across the 1.3 Ω resistor. Answer in units of V.
Find the current in the 10.0 Ω resistor. Answer in units of A.

Homework Equations


V = IR
Req = 1/R1 + 1/R2 + 1/R3 ...

The Attempt at a Solution


First, I calculated the equivalent resistance.
The top path - parallel circuit: 1/((1/7.7) + (1/7.7)) = 3.85 + 3.4 = 7.25​
The middle path - parallel circuit: 1/((1/4.6) + (1/10.0)) = 3.150684932 + 1.3 = 4.450684932​
Req = ?​
My teacher helped me at school and when I tried to do the problem on my own, using his steps, I forgot them all. Just yesterday I remember that I could get the equivalent resistance which is around 6.157 but I keep trying and trying but I can't seem to get that answer either. I need help on that part too.

Here is the total current: I = V / R -> I = 18.0 / 6.157 = approx. 2.92

I don't really understand how to find the current etc. It gives me headaches! Sorry the picture is kinda dark...
 
Last edited:
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Everything you have done is OK. Except the equation is

1/Req = 1/R1 + 1/R2 +...

Treat the top and middle paths as two parallel resistances and find their equivalent resistance before adding the final 3.4 Ohm. You will get the 6.157 Ohm value.

Then to answer questions 1 and 2 you have to work out how much of that 2.92 amperes of current will go though the middle branch.

For question 3 you conduct a similar investigation.
 

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