How do you solve for an exponent that is pi and a cube root?

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The discussion focuses on solving mathematical expressions where the exponent is π and involves cube roots. The identity used is \( a^{b} = e^{b \ln a} \), which allows for the transformation of expressions into a form suitable for calculation. Specific examples provided include \( e^{\ln 4.2} \), \( e^{\pi \ln 2} \), and \( e^{\frac{1}{3} \ln 73} \). The consensus is that while some cube roots can be calculated directly, most require the use of a calculator for accurate results.

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How do you solve when an exponent is pi?

And a cube root.

Thanks, sorry I'm slow.View attachment 3285
 

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OMGMathPLS said:
How do you solve when an exponent is pi?

And a cube root.

Thanks, sorry I'm slow.View attachment 3285
Once in a while you will have a "perfect" cube root, ala the cube root of 27, but in general you have to use a calculator.

-Dan
 
OMGMathPLS said:
How do you solve when an exponent is pi?

And a cube root.

Thanks, sorry I'm slow.View attachment 3285

In general for a > 0 the following identity holds...

$\displaystyle a^{b} = e^{b\ \ln a}\ (1) $

... so that the six numbers are $\displaystyle e^{\ln 4.2},\ e^{\pi\ \ln 2},\ e^{\frac{1}{2} \ln 15},\ e^{2.5\ \ln 2},\ e^{\frac{1}{3}\ \ln 73},\ e^{3\ \ln \pi}$, and at this point You have to work on the exponents...

Kind regards

$\chi$ $\sigma$
 
Thanks. I will put it in a calculator.
 

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