How do you solve for an exponent that is pi and a cube root?

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Discussion Overview

The discussion revolves around solving mathematical expressions involving an exponent of pi and a cube root. Participants explore methods for handling such expressions, including the use of calculators and mathematical identities.

Discussion Character

  • Exploratory, Mathematical reasoning

Main Points Raised

  • Some participants suggest that while certain cube roots can be "perfect," such as the cube root of 27, in general, a calculator is necessary for solving expressions involving pi as an exponent.
  • One participant presents a mathematical identity, $\displaystyle a^{b} = e^{b\ \ln a}$, to express various numbers in terms of exponentials, indicating that further work on the exponents is needed.
  • Another participant expresses intent to use a calculator to solve the problem, indicating a practical approach to the discussion.

Areas of Agreement / Disagreement

Participants do not reach a consensus on a specific method for solving the problem, and multiple approaches are presented without resolution.

Contextual Notes

The discussion includes assumptions about the use of calculators and the applicability of the mathematical identity presented, which may depend on the context of the numbers involved.

OMGMathPLS
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How do you solve when an exponent is pi?

And a cube root.

Thanks, sorry I'm slow.View attachment 3285
 

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OMGMathPLS said:
How do you solve when an exponent is pi?

And a cube root.

Thanks, sorry I'm slow.View attachment 3285
Once in a while you will have a "perfect" cube root, ala the cube root of 27, but in general you have to use a calculator.

-Dan
 
OMGMathPLS said:
How do you solve when an exponent is pi?

And a cube root.

Thanks, sorry I'm slow.View attachment 3285

In general for a > 0 the following identity holds...

$\displaystyle a^{b} = e^{b\ \ln a}\ (1) $

... so that the six numbers are $\displaystyle e^{\ln 4.2},\ e^{\pi\ \ln 2},\ e^{\frac{1}{2} \ln 15},\ e^{2.5\ \ln 2},\ e^{\frac{1}{3}\ \ln 73},\ e^{3\ \ln \pi}$, and at this point You have to work on the exponents...

Kind regards

$\chi$ $\sigma$
 
Thanks. I will put it in a calculator.
 

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