How Do You Solve for Normal Force in Different Dynamics?

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Homework Help Overview

The problem context involves determining the normal force acting on a car rolling over the top of a hill, with considerations of various forces at play, particularly in dynamic scenarios. The subject area relates to dynamics and forces, specifically the normal force in different contexts.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the framework for understanding normal force, with one participant reflecting on their initial assumptions about normal force being equal to the perpendicular component of gravitational force. Questions arise regarding the nature of the car's velocity and acceleration as it moves over the hill, as well as the various contexts in which normal force can be defined.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of normal force and its relationship to the motion of the car. Some guidance has been offered regarding the need to consider the resulting motion of the object when determining the normal force, though no consensus has been reached.

Contextual Notes

Participants are navigating the complexities of normal force in dynamic situations, questioning assumptions about its constancy and the conditions under which it can be evaluated. The original poster expresses uncertainty about their understanding of the normal force in various scenarios.

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Homework Statement



The problem motivating this post is: "An out-of-gas car is rolling over the top of a hill at speed v. At this instant,
a. n > FG
b. n < FG
c. n = FG
d. We can't tell about n without knowing v." (Associated figure attached.)

Homework Equations


[/B]
Newton's second law

The Attempt at a Solution



What I'd like to understand is in what framework to think about the normal force.

I currently understand the normal force to be equal and opposite to the perpendicular force exerted by an object on the surface with which it is in contact. I still believe this to be correct.

I'm wrestling with how to solve for the normal force. Originally, I assumed it was always equal and opposite to the perpendicular component of the force of gravity, such as is the case in a standard incline plane problem. To solve for the normal force, I would first solve for the perpendicular component of the force of gravity, then flip the sign. However, the motivating problem I posted above, as well as examining a car doing a vertical loop-the-loop and driving around a curve on a banked track, has shown that this framework for solving for the normal force can be faulty.

It now appears that, to solve for the normal force acting on an object, I should first determine the resulting motion of the object known to be true in a given scenario and then set the normal force equal to whatever force is required to make that motion result. So, in the motivating problem above, because I know the car will roll down the other side of the hill, the downward force of gravity must exceed the upward normal force, and the answer must be "b".

Is this line of thinking how you understand to solve for the normal force?

The paradigm of "first determine how you know the system to act, then set a force equal to whatever is required to make the system act in that way" feels foreign to me. I'm used to "first solve for all the forces, then determine how the system will act as a result of those forces."
 

Attachments

  • Car Rolling Over Hill.jpg
    Car Rolling Over Hill.jpg
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Is the direction of the car's velocity vector constant as the car goes over the hill, or is it changing? What does this tell you about the car's acceleration? What does that tell you about the net force acting on the car?

Chet
 
What normal force did you have in mind?

There is the normal force between the wheel and the road;
the normal force between the air and the car;
the normal force between the axle and the car body,
etc.
 
@Old: come on, a clear picture is provided !

@IMP: Chet's chat makes good sense to me !
 

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