When would the normal force not equal the weight?

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Homework Help Overview

The discussion revolves around the conditions under which the normal force acting on an object does not equal its weight, particularly in static situations. Participants explore scenarios involving forces acting in the vertical direction and the implications for normal force in various contexts.

Discussion Character

  • Conceptual clarification, Assumption checking, Mixed

Approaches and Questions Raised

  • Some participants question the assumption that normal force always equals the weight of an object, suggesting that additional forces can alter this balance. Others provide examples, such as the effect of an upward force or multiple objects stacked on one another, to illustrate situations where normal force differs from gravitational force.

Discussion Status

The discussion is active, with participants offering examples and questioning the foundational concepts of normal force and weight. There is a recognition of different scenarios that can lead to variations in normal force, but no consensus has been reached on a definitive explanation.

Contextual Notes

Participants are considering specific setups, such as objects on slopes and the interaction between stacked objects, which may influence the normal force. The discussion also references external resources for further exploration of common misconceptions in mechanics.

gungo
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Homework Statement


I know that on a horizontal surface. if the net force is 0 in the y direction the weight of object=the normal force, but wouldn't the normal force always equal the magnitude of gravity on an object, just in opposite directions? Because if the weight is stronger than the normal force or vice versa, the object would move in the y direction, but objects don't fall through the ground or randomly or start floating so I'm kind of confused.

Homework Equations


Fg=mg

The Attempt at a Solution


N/A
 
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Assuming a statics situation ##\sum \mathbf F = 0##, there are conceivable situations in which the normal force wouldn't equal the force of gravity. One example is if you were applying a light upward force on the object from a hand or string or something that isn't strong enough to actually pick it up. In this case, the normal force would equal the force of gravity minus the applied upward force.
 
gungo said:

Homework Statement


I know that on a horizontal surface. if the net force is 0 in the y direction the weight of object=the normal force, but wouldn't the normal force always equal the magnitude of gravity on an object, just in opposite directions? Because if the weight is stronger than the normal force or vice versa, the object would move in the y direction, but objects don't fall through the ground or randomly or start floating so I'm kind of confused.

Homework Equations


Fg=mg

The Attempt at a Solution


N/A
Normal force between two surfaces is the minimum magnitude force which prevents their interpenetration. Thus, it is always normal to the contact plane.
If an object is placed on a frictionless slope, the normal force only has to counter the component of gravity normal to the plane. The other component leads the object to slide down.

See also https://www.physicsforums.com/insights/frequently-made-errors-vectors-elementary-use and https://www.physicsforums.com/insights/frequently-made-errors-mechanics-friction/
 
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