How Do You Solve for the Time Given Initial Velocity and Angle?

In summary, the time for the ball to reach its highest point can be found using the equation V^2 = Vi^2 + 2(a)(y) or by using the simpler equation V_{f}=V_{i}+at, which yields a time of 1.37 seconds.
  • #1
papa_smurf493
30
0

Homework Statement


A left-handed pitcher at sea level throws a baseball at a 45o angle with an initial speed of 19 m/s. The time for the ball to reach its highest point can be found from the data and known constants using which equations? Solve for the time.



Homework Equations


V^2 = Vi^2 + 2(a)(y)
y = (Vi)(t) + 1/2(a)(t^2)


The Attempt at a Solution


V^2 = Vi^2 + 2(a)(y)
0 = 13.435^2 + 2*9.8*y
y = 9.21 meters

9.21 = 0 + 0.5*9.8*t^2
9.21 = 4.9*t^2
t = 1.37 seconds
 
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  • #2
Yes, correct, but you could have shortened your work by using just one simpler equation. Can you identify that equation?
 
  • #3
Looks okay.
I used this:
V[tex]_{f}[/tex]=V[tex]_{i}[/tex]+at

velocity at the highest point is 0, so..

0[tex]m/s[/tex] =19[tex]m/s[/tex] sin45°-9.8[tex]m/s^{2}[/tex] *t
t=1.37s
 

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