How Do You Solve for the Time Given Initial Velocity and Angle?

  • Thread starter Thread starter papa_smurf493
  • Start date Start date
  • Tags Tags
    Check my work Work
Click For Summary
SUMMARY

The discussion focuses on calculating the time it takes for a baseball, thrown at a 45-degree angle with an initial speed of 19 m/s, to reach its highest point. The solution involves using the kinematic equations, specifically V^2 = Vi^2 + 2(a)(y) and y = (Vi)(t) + 1/2(a)(t^2). The calculated time to reach the peak is 1.37 seconds, derived from the equation V_{f}=V_{i}+at, where the final velocity at the peak is zero. The discussion emphasizes the efficiency of using the simpler equation for quicker results.

PREREQUISITES
  • Understanding of kinematic equations in physics
  • Knowledge of projectile motion concepts
  • Familiarity with trigonometric functions, specifically sine
  • Basic algebra skills for solving equations
NEXT STEPS
  • Study the derivation and application of kinematic equations in projectile motion
  • Learn about the effects of air resistance on projectile trajectories
  • Explore advanced topics in physics such as vector decomposition
  • Investigate real-world applications of projectile motion in sports science
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and projectile motion, as well as educators looking for examples of kinematic equations in action.

papa_smurf493
Messages
30
Reaction score
0

Homework Statement


A left-handed pitcher at sea level throws a baseball at a 45o angle with an initial speed of 19 m/s. The time for the ball to reach its highest point can be found from the data and known constants using which equations? Solve for the time.



Homework Equations


V^2 = Vi^2 + 2(a)(y)
y = (Vi)(t) + 1/2(a)(t^2)


The Attempt at a Solution


V^2 = Vi^2 + 2(a)(y)
0 = 13.435^2 + 2*9.8*y
y = 9.21 meters

9.21 = 0 + 0.5*9.8*t^2
9.21 = 4.9*t^2
t = 1.37 seconds
 
Physics news on Phys.org
Yes, correct, but you could have shortened your work by using just one simpler equation. Can you identify that equation?
 
Looks okay.
I used this:
V[tex]_{f}[/tex]=V[tex]_{i}[/tex]+at

velocity at the highest point is 0, so..

0[tex]m/s[/tex] =19[tex]m/s[/tex] sin45°-9.8[tex]m/s^{2}[/tex] *t
t=1.37s
 

Similar threads

Replies
11
Views
2K
  • · Replies 38 ·
2
Replies
38
Views
4K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 3 ·
Replies
3
Views
1K
Replies
11
Views
3K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 6 ·
Replies
6
Views
5K
Replies
9
Views
4K
Replies
10
Views
4K
  • · Replies 1 ·
Replies
1
Views
2K