How Do You Solve for Time in the Equation d = 0.5(at^2)?

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To solve for time in the equation d = 0.5(at^2), the equation can be rearranged to d = (at^2)/2. By manipulating this, one can express acceleration as A = 2d/t^2. Ultimately, the solution for time is t = square root of (2d/a). This method provides a clear path to isolate time in the original equation.
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1. d = 0.5 (at^2) solve for t in terms of a and d

Probably really simple but I have no clue where to start from...
 
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d=(at^2/2) is the same as your equation, and try and solve from that
 
d = 0.5(a)(t^2), maybe that will help.
 
Alright I think I got it. A= 2d/t^2, t = square root of 2d/a.
 

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