How do you solve for x in 1 = 2/(x+3)?

[questions_uk]

hi. really simple maths question but how do you re-arrange

1 = 2 / (x + 3)

to make x the subject?

do you make (x + 3) the subject first?

Thanks!

 

[CompuChip]

There are several ways to do it.

You can substitute y = x + 3 and make y the subject, as you suggested, then substitute it back and solve for x.

You can use the balance method (basically "any operation is allowed, as long as you do it on both sides") to multiply by (x + 3) and get it out of the denominator.

Or you can write 1 = 1 / 1 and use either the balance method to "flip" both fractions (cf. a/b = c/d is equivalent with b/a = d/c as long as a, c are non-zero) or cross-multiply (cf. a/b = c/d is equivalent with a d = b c).

All of these lead to the same result (hopefully).

In general you want to take the x outside of fractions, brackets, etc. and then sweep them all to one side.

 

[questions_uk]

Thanks for the reply although I was wondering if you could provide the steps to make x the subject so that it could be understood a lot better. These are not the actual numbers in the question.

 

[questions_uk]

Nevermind I got it. Thanks.