How Do You Solve Inverse Functions in Algebra Problems?

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    Algebra Grade 11
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To solve inverse functions in algebra, start with the function g(t) = 3t - 2. For g^(-1)(-2), the calculation involves rearranging the equation to find t, resulting in g^(-1)(-2) = -4/3. The second part, g^(-1)(a+1) - g^(-1)(a), requires understanding how changes in the input affect the output of g. Specifically, it asks how much x must increase for g(x) to increase by 1, which involves determining the rate of change in the function. Understanding these concepts is crucial for correctly solving inverse function problems.
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Having trouble with this question. Usually i'd have to see examples first and rep it out but time ran out of class and i guess we couldn't see them. He gaves us tons of notes though but I'm not really sure if I'm doing it right.

Homework Statement


for g(t) = 3t-2, determine each of the following.

(the -1 is an inverse..)
a. g -1 (-2)
b. g -1(a+1) - g -1(a)

Homework Equations





The Attempt at a Solution



Here's what i did with the g -1(-2)

g(t)=3t-2
t=3g(t)-2
(t-2)/3=g(t)
(-2-2)/3 = -4/3

I have no idea how to do the next one though. Well yea i do but it's probably completely wrong.
 
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For the next one, you're taking the difference of two values such that, when you apply g to them, one gives you a value 1 larger than the other. How much does x have to increase by for g(x) to increase by 1?
 

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