How Do You Solve Non-linear Second Order Differential Equations?

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Homework Help Overview

The discussion revolves around solving non-linear second order differential equations, with participants exploring the nature of the equation and the methods for finding solutions.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants question the classification of the equation as non-linear, with some suggesting it may still be linear despite the presence of a squared term. Others inquire about methods for obtaining solutions and the validity of proposed solutions.

Discussion Status

The discussion is active, with participants offering guidance on checking solutions by substituting back into the original equation. There is a mix of interpretations regarding the linearity of the equation and the nature of the solutions, with no explicit consensus reached.

Contextual Notes

Some participants express uncertainty about the methods to derive solutions and the implications of approximations in the context of the differential equation.

athrun200
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Homework Statement



attachment.php?attachmentid=36816&stc=1&d=1309339678.jpg


Homework Equations





The Attempt at a Solution



I just want to ask how to obtain the solution?
What mathematical method involved?
 

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Replace back the given function into the differential equation and see if it is really the solution.

ehild
 
What makes you think this is Non Linear?
 
ehild said:
Replace back the given function into the differential equation and see if it is really the solution.

ehild


I just want to know, if I only have the first line, how can I get second line?
Just by try and error?
 
Saladsamurai said:
What makes you think this is Non Linear?

I see there is a square there.:-p
 
athrun200 said:
I just want to know, if I only have the first line, how can I get second line?
Just by try and error?

Is the second line solution of the differential equation?

ehild
 
athrun200 said:
I see there is a square there.:-p

It's still linear because neither psi nor the second derivative of psi is being squared. However, the second line isn't the solution, and there's no solution in terms of elementary functions:

http://www.wolframalpha.com/input/?i=y%27%27%3Dx^2*y
 
ideasrule said:
It's still linear because neither psi nor the second derivative of psi is being squared. However, the second line isn't the solution, and there's no solution in terms of elementary functions:

http://www.wolframalpha.com/input/?i=y%27%27%3Dx^2*y
I saw the eqtn from this book.
Does it mean that the approximation is wrong?

attachment.php?attachmentid=36838&stc=1&d=1309409900.jpg
 

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If you calculate the second derivative of Ψ=exp(±z2/2) you will find that it is (z2±1)Ψ. Therefore the Ψ-s are only approximate solution, valid for z2>>1.

ehild
 

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