How Do You Solve the Limit Involving Tangent and Sine Functions?

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abruski
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Homework Statement


[tex]\lim_{x \rightarrow \frac{\pi}{4}} \frac{\sqrt[3]{tgx} - 1}{2sin^2x-1}[/tex]

Homework Equations


The Attempt at a Solution


I don't even know where to begin
 
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abruski said:

Homework Statement


[tex]\lim_{x \rightarrow \frac{\pi}{4}} \frac{\sqrt[3]{tgx} - 1}{2sin^2x-1}[/tex]


Homework Equations





The Attempt at a Solution


I don't even know where to begin

Does tgx mean tan(x)? If that's what is meant, tgx is very unclear.

Assuming that tan(x) is what we're dealing with, the limit has the indeterminate form [0/0], so L'Hopital's Rule is applicable.