How Do You Solve These Simultaneous Linear Equations for L and X?

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Homework Help Overview

The problem involves finding the values of L and X from two equations that include squared terms, suggesting a non-linear relationship. The equations are presented in a mathematical context related to simultaneous equations.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss the nature of the equations, with one noting that they are not linear due to the squared terms. There is mention of using substitution as a potential method to solve the equations, along with inquiries about previous attempts and results.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the problem. Some guidance has been offered regarding substitution, but there is no explicit consensus on a solution or method yet.

Contextual Notes

There is a suggestion that the original poster may be struggling with the non-linear nature of the equations, and there is an emphasis on understanding the implications of squaring the variables.

Loke
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Homework Statement


Find value L and X.

0.182(L2+X2)=1602
0.182[(555.56+L)2+X2]=2402
 
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Technically, these aren't linear equations, are they, since both L and X are squared. You can solve this through substitution. I would solve the 1st equation for X2, then substitute the result into the 2nd equation and then solve for L. Try it, and let us know what you get.


69
 
but i still don't know why i can't solve it out ...can you show me how you do it? ^^
 
Well, what have you tried to do? Have you solved [itex]0.18^2(L^2+ X^2)= 160^2[/itex]? If so, what did you get?

What equation do you get when you replace [itex]X^2[/itex] by that in [itex]0.182[(555.56+L)^2+X^2]=2402[/itex]?
 

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