How Do You Solve This Arithmetico-Geometric Series?

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SUMMARY

The discussion focuses on solving the infinite arithmetico-geometric series defined as S = ∑ (n+1)/4^n for n=0 to infinity. Participants suggest breaking the series into simpler components, specifically separating it into multiple geometric series. A recommended method involves multiplying the series by a variable x, integrating, and then differentiating to find a closed form solution. Setting x=1 at the end yields the desired sum.

PREREQUISITES
  • Understanding of geometric series and their properties
  • Familiarity with series manipulation techniques
  • Basic knowledge of calculus, particularly integration and differentiation
  • Experience with summation notation and limits
NEXT STEPS
  • Study the derivation of arithmetico-geometric series sums
  • Learn about the method of generating functions for series
  • Explore integration techniques for series summation
  • Investigate the application of differentiation in series solutions
USEFUL FOR

Students and educators in mathematics, particularly those focused on series and calculus, as well as anyone looking to deepen their understanding of arithmetico-geometric series and their applications.

eNathan
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Trying to solve this infinite series??

Hey folks! I've spent hours trying to solve this and have exhausted all available resources.. I just need to be pointed in the right direction!

Homework Statement


Compute the sum of the infinite series (I believe this is an arithmetico geometric series):
\sum \frac{n+1}{4^{n}}

For n=0..infinity

Homework Equations


I know the standard way to solve a geometric series, but don't know how to solve this type of series.


The Attempt at a Solution


I've set up something like this:
S_{n} = \sum \frac{n+1}{4^{n}}
I've tried multiplying by 1/4, 4 and other logical things, but am just not sure how to proceed.

Thanks in advance!
 
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Your expression can be written as
$$\sum_0^\infty \frac{1}{4^{n}} + \sum_1^\infty \frac{1}{4^{n}} + \sum_2^\infty \frac{1}{4^{n}} + \dots$$
(This assumes you start your sum at 0, if you start at 1 you have to modify it a bit.)
 
Another approach, perhaps more general in application, is to multiply the terms by xn then integrate. You should then be able to sum the series into closed form and differentiate to get a closed form for the original sum. Finally set x=1.
 

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