How Do You Solve Vector Velocity in 3D?

1 reply · 2K views · last reply
jmagic
Messages
1
Reaction score
0

Homework Statement



Typeset problem statement: velocity v(t) = 6i + (6t^5 + 2)j - 2e^(-t) ln(e) k; initial position r(0) = <2, 2, 2>; find the acceleration a(t) and the position r(t).


Homework Equations


i+j+k=1, <1,1,1>


The Attempt at a Solution



a(t)=i+(30t^(4))j+(2e^(-t)ln(e)-2e^(-t)(1/e))k
r(t)=(2+6t)i+(2+t^6+2t)j+(2+2e^-t)k




[

1. The problem statement, a
 
Welcome to PF!

Hi jmagic! Welcome to PF! :smile:
jmagic said:
r(t)=(2+6t)i+(2+t^6+2t)j+(2+2e^-t)k

i and j are correct, but the constant in k is wrong …

hint: e0 = … ? :smile:
a(t)=i+(30t^(4))j+(2e^(-t)ln(e)-2e^(-t)(1/e))k

Hint: 6 and ln(e) are constants, aren't they? :wink: