How Do You Square Cosine B?

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Homework Help Overview

The discussion revolves around the mathematical operation of squaring the cosine function, specifically cosB. Participants are exploring the implications and methods of squaring this trigonometric function.

Discussion Character

  • Exploratory, Conceptual clarification

Approaches and Questions Raised

  • Some participants question the clarity of the original poster's inquiry regarding squaring cosB. Others suggest that cosB can be treated like any real number when squared. There is also a mention of the potential for infinite solutions related to the equation involving cosB.

Discussion Status

The discussion is ongoing, with participants seeking clarification on the original question. Some guidance has been offered regarding the nature of squaring a real number, but there is no explicit consensus on the intended question or the approach to take.

Contextual Notes

There is a lack of detailed context regarding the specific equation or scenario in which cosB is being squared, which may affect the clarity of the discussion.

chemic_23
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Homework Statement



square.jpg


Homework Equations



how do you square cosB?

The Attempt at a Solution

 
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Hi chemic_23, well you haven't really asked a question. In answer to you how do you square [itex]cos\beta[/itex] (i assume that's what you meant) you can square it like any other number as [itex]\textbf{cos\beta}[/itex] will be a real number if beta is a real number. Is you question find the solutions to this equation, because there are an infinite number of them?

If you could clarify you question then I am sure you'll find the help you need :D
 


I'm trying to understand this part of solution
square2.jpg

but I don't have any idea on how to square the cosB... It just came out with no detailed solution... please help
 


if you have f(l) = (x + y) / z where x,y,z are constants

remember you can always change that to

x /z + y/z

and then what would be f^2 (l)

(x /z + y/z)^2 = (x /z + y/z)(x /z + y/z)

and you can expand that right?
 


thanks:)
 

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