- #1

- 1,169

- 132

- Homework Statement
- Pleases see below

- Relevant Equations
- Please see below

For this problem,

The solution is,

I understand their logic for their equation, but when I was trying to solve this problem, I came up with a different expression:

##\Delta A = \Delta L_x\Delta L_y##

##\Delta L_x =\Delta L_y = \Delta L## since this is a square.

##\Delta A = \Delta L^2##

##\Delta A = \alpha^2L_i^2\Delta T^2##

I also don't understand how how ##\Delta T = 50K## since it should be converted to celsius since the coefficient of linear expansion is in has unit of inverse celsius.

I did that and got ##\Delta T = -223.15 °C## from ##T_k = T_c + 273.15##

Many thanks!

The solution is,

I understand their logic for their equation, but when I was trying to solve this problem, I came up with a different expression:

##\Delta A = \Delta L_x\Delta L_y##

##\Delta L_x =\Delta L_y = \Delta L## since this is a square.

##\Delta A = \Delta L^2##

##\Delta A = \alpha^2L_i^2\Delta T^2##

I also don't understand how how ##\Delta T = 50K## since it should be converted to celsius since the coefficient of linear expansion is in has unit of inverse celsius.

I did that and got ##\Delta T = -223.15 °C## from ##T_k = T_c + 273.15##

Many thanks!