How do you visualise the atomic orbitals?

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SUMMARY

This discussion focuses on visualizing atomic orbitals and understanding electron behavior in quantum mechanics. It emphasizes that orbitals represent stationary states and cannot define electron trajectories due to the Heisenberg uncertainty principle. The conversation outlines the Bohr model's circular orbitals (K, L, M, N) and the SPDF configuration, which describes the probability distribution of electrons in various orbitals. For practical visualization, users are directed to the Falstad quantum mechanics simulator, which provides a 3D model of orbitals and their probability densities.

PREREQUISITES
  • Understanding of quantum mechanics principles, specifically the Heisenberg uncertainty principle
  • Familiarity with atomic structure, including quantum numbers and orbital types (S, P, D, F)
  • Knowledge of the Schrödinger equation and its implications for electron behavior
  • Basic understanding of probability distribution functions in quantum mechanics
NEXT STEPS
  • Explore the Falstad quantum mechanics simulator for interactive visualization of atomic orbitals
  • Study the implications of the Schrödinger equation on electron behavior and orbital shapes
  • Research the differences between classical and quantum mechanical models of atomic structure
  • Learn about the significance of quantum numbers in determining electron configurations
USEFUL FOR

Chemistry students, physics enthusiasts, educators, and anyone interested in the visualization and understanding of atomic orbitals and electron behavior in quantum mechanics.

Nethrz
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I do know the shapes of the individual orbitals but as a whole, I'm confused as to how to visualise their positions...Also how can we predict the trajectory of an electron or can it not be predicted because of Heisenberg's uncertainty principle
 
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Orbitals represent stationary states, i.e., states that do not change with time. You cannot talk about the trajectory of an electron in an orbital, only the probability that it will be found at a certain position around the nucleus.

For the purposes of chemistry, I think it is best to see it as the electron being spread out over the orbital. It is a classical picture that is not completely correct, but useful.
 
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You could imagine orbitals on different levels with increasing complexity and correctness

First would be bohr orbitals, which are the circular orbital energy shells K,L,M,N and so on where 2,8,8,18,32...goes on

Second would be SPDF configuration where orbitals are basically a certain region where probability of finding the electron is.For example the probability of finding a electron in S orbital is maximum at the centre and minimum at the edges .For P orbital a node comes in play where the probability of finding a electron is 0 and it is maximum as we go farther away but not too far away outside the orbital.Similarly for D, F etc. It is given by a probability distribution function which gives us this information

You can view this here at falstad :
https://www.falstad.com/qmmo/

All the other things about the electron are derived from the schrödinger equation except the spin quantum number. Principal quantum number tells you which energy level it lies on i.e n=1,2,3....and so on . Azimuthal quantum number tells you the orbital i.e S,P,D or F and .Magnetic quantum number tells you the subshell i.e the subshell of orbital in different axis like P(x),P(y) and P(z) .Spin quantum number tells you the spin of electron i.e +1/2 or -1/2.
As for the positions of the orbitals they overlap on and into each other creating concentric shapes which hold the electrons(according to spdf model) even if you dont understand this go to the falstad link above to visualise it ,it gives you a 3d model along with probability density
 
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I came.across a headline and read some of the article, so I was curious. Scientists discover that gold is a 'reactive metal' by accidentally creating a new material in the lab https://www.earth.com/news/discovery-that-gold-is-reactive-metal-by-creating-gold-hydride-in-lab-experiment/ From SLAC - A SLAC team unexpectedly formed gold hydride in an experiment that could pave the way for studying materials under extreme conditions like those found inside certain planets and stars undergoing...

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