How Does (1+x)^r Compare to 1+rx for 0<r<1 and Specific x Values?

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Homework Help Overview

The discussion revolves around comparing the expressions (1+x)^r and 1+rx for the case where 0

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the use of the binomial theorem to expand (1+x)^r and consider the implications of the constraints on r and x. There are attempts to isolate variables and relate them, but some express uncertainty about the initial conditions and their implications.

Discussion Status

The conversation is ongoing, with some participants offering guidance on using the binomial theorem while others question the clarity of the problem statement regarding the conditions on x. Multiple interpretations of the problem are being explored.

Contextual Notes

There is a noted ambiguity in the statement regarding the conditions on x, which some participants are seeking to clarify. The absence of relevant equations in the original posts may also be influencing the discussion.

~Sam~
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Homework Statement



Let 0< r <1. If x>0 or -1 less than or equal x <0. SHOW THAT (1+x) ^ r <1+rx


Homework Equations



no relevant equations


The Attempt at a Solution



I've tried isolating, but I can't relate x to x or r to r. I can't split the equation because I don't know r.
 
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Try using the binomial theorem to expand (1+x)r and then think about what 0<r<1 and -1≤x<0 really means for your expansion.
 
~Sam~ said:

Homework Statement



Let 0< r <1. If x>0 or -1 less than or equal x <0. SHOW THAT (1+x) ^ r <1+rx


Homework Equations



no relevant equations


The Attempt at a Solution



I've tried isolating, but I can't relate x to x or r to r. I can't split the equation because I don't know r.

"If x>0 or -1 less than or equal x <0."--->I think this statement has some problem.
 
blake knight said:
"If x>0 or -1 less than or equal x <0."--->I think this statement has some problem.

No there is no problem, it's X > 0 OR
 

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