How Does a Changing Magnetic Field Induce EMF in a Circular Loop?

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SUMMARY

The discussion focuses on the calculation of induced electromotive force (emf) and current in a circular wire loop subjected to a changing magnetic field described by B = 2cos(2t). The induced emf is derived using the equation \(\epsilon = -d\Phi/dt\), resulting in \(\epsilon = -4\pi r^2 \sin(2t)\). The relationship between induced current and emf is established with \(I = \epsilon/R\), leading to \(I = -4\pi r^2 \sin(2t)/R\). The participants emphasize the importance of considering only the perpendicular component of the magnetic field in the calculations.

PREREQUISITES
  • Understanding of Faraday's Law of Electromagnetic Induction
  • Familiarity with calculus, specifically differentiation
  • Knowledge of circular motion and geometry related to circular loops
  • Basic concepts of electromagnetic fields and their interactions
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  • Study the application of Faraday's Law in different geometries
  • Learn about the implications of Lenz's Law in induced currents
  • Explore the relationship between frequency and induced emf in AC circuits
  • Investigate the effects of varying magnetic fields on different loop configurations
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Homework Statement



Resistance = R
Radius = r
Angle = theta
B = 2cos(2t)
Circular wire loop where magnetic field acts at theta degrees with respect to the normal of the wire loop.
Find induced current and emf in wire loop. Find induced electric field at radial distance d from center of wire loop.

Homework Equations



\epsilon = -d\Phi/dt
I = \epsilon/R

The Attempt at a Solution



A = \pir^{}2
\epsilon = d(BA)/dt
= A dB/dt
= \pir^{}2 d(2cos(2t))/dt
= -4\pir^{}2 sin(2t) = induced emf (area not changing)

Given a magnetic field B with a constraint of 2t for \omegat, and no time, the answer must be with respect to t, correct? You can't use the frequency given by 2/2pi can you?

i = \epsilon / R
i = -4\pir^{}2 sin(2t) / R

Since I still don't know time I'm guessing I have to solve as a function of t?

\epsilon = dB/dt d/2 = -2sin(2t)d
 
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There should be a sin(theta) or cos(theta) in the expression for emf because only the part of B that is perpendicular to the coil causes emf.

Other than that, your calcs look good to me except for the very last line, which I don't understand at all. Leave the sin(2t) in your answers - don't try to solve for t.
 
Oh right, I forgot that :) Still trying to figure out the last part. Thanks
 

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