How Does a Charge Distribution with Zero Total Charge Exist?

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Homework Help Overview

The discussion centers around a charge distribution characterized by a specific electric potential and charge density that results in a total charge of zero. Participants are exploring the implications of this configuration and seeking to understand the physical representation of the charge density.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants are attempting to visualize the charge density and question how a zero total charge can arise from a non-zero charge density. Some suggest simplifying the charge density expression to better understand its implications. Others discuss the nature of the charge distribution in relation to physical systems, such as plasma.

Discussion Status

The discussion is ongoing, with participants providing insights into the charge distribution and its physical context. Some have offered interpretations of the charge density's shape and its relation to spherical symmetry, while others have raised questions about the calculations leading to the conclusion of zero total charge.

Contextual Notes

Participants are considering the implications of charge screening in plasma and drawing analogies to systems like spherical capacitors. There is a focus on understanding the mathematical derivation of total charge and its physical significance.

humo90
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Need a physical picture!

The electric potential of some charge configuration is given by V(r) = A*e^(-λr) / r

Its Electric field is E = A*[(λr+1)/(r^2)]*e^(-λr) [itex]\hat{r}[/itex]

And its charge density is ρ = 4*pi*A*ε0*δ(r) - [(ε0*(λ^2)*A*e^-λr) / r] , where δ(r) is delta function.

The thing that surprised me is the total charge is zero (Q = 0), how could this happened since I have a charge density? and can someone help me answering the following two questions.

1. What is the physical picture of the charge density (=how does the charge density look
like)?

2. Where could a charge density of this form appear in nature?
 
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The electric potential of some charge configuration is given by V(r) = A*e^(-λr) / r

Its Electric field is E = A*[(λr+1)/(r^2)]*e^(-λr) rˆ

And its charge density is ρ = 4*pi*A*ε0*δ(r) - [(ε0*(λ^2)*A*e^-λr) / r] , where δ(r) is delta function.

The thing that surprised me is the total charge is zero (Q = 0), how could this happened since I have a charge density? and can someone help me answering the following two questions.

1. What is the physical picture of the charge density (=how does the charge density look
like)?

2. Where could a charge density of this form appear in nature?

Hi, How have you figured out that the total charge is zero exactly?

For a picture of the charge density its worth simplifying the statement of charge density by putting all the constants together, unless I have made a mistake does this make sense?

[itex]ρ(r)=B*δ(r)-C\frac{e^{-Dr}}{r}[/itex]

It is then a case of taking several significant values of radial points (it should already be clear it is spherically symmetric) and considering the value of the charge density given that B and C are positive. Does this help?

Once you have the shape and given the spherical nature the second question should make more sense.
 


A charge distribution of this nature appears when you place a point charge in a plasma. The point charge is screened by the ions/electrons of the plasma.
 


gash789 said:
Hi, How have you figured out that the total charge is zero exactly?

For a picture of the charge density its worth simplifying the statement of charge density by putting all the constants together, unless I have made a mistake does this make sense?

[itex]ρ(r)=B*δ(r)-C\frac{e^{-Dr}}{r}[/itex]

It is then a case of taking several significant values of radial points (it should already be clear it is spherically symmetric) and considering the value of the charge density given that B and C are positive. Does this help?

Once you have the shape and given the spherical nature the second question should make more sense.

To get the total charge, I took the volume integral of the charge density, that is

Q = ∫ρ dv = ∫(4*pi*A*ε0*δ(r) - [(ε0*(λ^2)*A*e^-λr) / r]) dv

= (4*pi*A*ε0) ∫δ(r) dv - (ε0*(λ^2)*A) ∫((e^-λr) / r) dv

= (4*pi*A*ε0) - (ε0*(λ^2)*A) ∫∫∫((e^-λr) / r) (r^2)*sin(∅)*dr*d∅*dθ,

since ∫δ(r) dv = 1

and dv = (r^2)*sin(∅)*dr*d∅*dθ in spherical coordinates.

Also, ∫∫∫((e^-λr) / r) (r^2)*sin(∅)*dr*d∅*dθ = (4*pi*ε0*(λ^2)*A)((1/λ^2)-((r*e^-λr)/λ)-((e^-λr)/(λ^2)),

and for entire space: r goes to ∞, we get ∫∫∫((e^-λr) / r) (r^2)*sin(∅)*dr*d∅*dθ = (4*pi*ε0*A).

Hence, Q = (4*pi*A*ε0) - (4*pi*ε0*A) = 0

I am really still confusing about understanding this problem.
 


Hi, your working appears correct. I am not 100% but taking Dickfore answer this solution would make sense. The total enclosed charge is zero due to screening by the plasma. Sorry I can't be of any help
 


humo90 said:
The thing that surprised me is the total charge is zero (Q = 0), how could this happened since I have a charge density? and can someone help me answering the following two questions.

There is a positive point charge in the middle and negative charge distribution around. It is somewhat similar to a spherical capacitor with a very small inner sphere, with positive charge, and a grounded outer sphere where negative charges accumulate. There is an electric field between the spheres, there is a charge distribution, and the total charge of the capacitor is zero.

ehild
 

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