How Does a Dielectric Influence Charge Induction on a Conducting Shell?

Click For Summary
SUMMARY

The discussion centers on the influence of a dielectric on charge induction in a conducting spherical shell surrounding a charged conducting sphere. The key equations referenced include the electric displacement field equation, ##D=\epsilon_0E + P##. It is established that the dielectric's polarization leads to a charge distribution ##\sigma## at the interface with the conducting shell, which is influenced by both the dielectric's bounded surface charge ##\sigma_b## and the charge ##Q## on the sphere. The reasoning confirms that while the conducting shell has no net free charge, induced charges can exist on its inner surface due to the electric field and displacement field discontinuities.

PREREQUISITES
  • Understanding of electrostatics, specifically Gauss's Law
  • Familiarity with dielectric materials and their polarization effects
  • Knowledge of electric fields and electric displacement fields
  • Basic principles of charge induction in conductors
NEXT STEPS
  • Study Gauss's Law applications in electrostatics
  • Explore the properties of dielectrics and their impact on electric fields
  • Learn about charge distribution in conductors under electrostatic conditions
  • Investigate the relationship between electric displacement field and polarization
USEFUL FOR

This discussion is beneficial for physics students, electrical engineers, and anyone studying electrostatics and charge induction phenomena in conductive materials.

Karl86
Messages
40
Reaction score
3

Homework Statement


Imagine having a conducting sphere with free charge ##Q## surrounded by a spherical shell filled with a dielectric and then a conducting spherical shell with no free net charge. I want to find out the charge induced on the spherical conducting shell by the sphere or by the dielectric.

Homework Equations


##D=\epsilon_0E + P##

The Attempt at a Solution


The dielectric being polarized, at its interface with the conducting spherical shell there will be a charge distribution ##\sigma## attracted by the bounded surface charge ##\sigma_b## of the dielectric and also by the charged sphere. Thus both the electric field ##E## and the electric displacement field ##D## will be discontinuous. Even though there is no free net charge in the spherical shell. Is this reasoning correct?
In other words, my doubt can be restated: is there some free charge at the inner surface of the spherical shell, even though the conducting shell has no net free charge?
 
Physics news on Phys.org
You are on the right track. Consider a spherical concentric Gaussian surface entirely inside the conducting shell.
1. What is the electric flux through the surface?
2. What does the answer to the previous question imply about the free charge enclosed by the surface?
3. What do the answers to the previous two questions imply about the free charge on the outer surface of the conducting shell?
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
1K
Replies
23
Views
5K
  • · Replies 9 ·
Replies
9
Views
3K
Replies
7
Views
2K
  • · Replies 23 ·
Replies
23
Views
2K
Replies
5
Views
4K
Replies
2
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 15 ·
Replies
15
Views
4K
  • · Replies 19 ·
Replies
19
Views
4K