- #1

Granger

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## Homework Statement

Consider a spherical conducting shell with inner radius R2 and outer radius R3, that has other spherical conductor inside it with radius R1 (this one is solid). Initially the 2 spheres are connected by a wire. We put a positive charge Q on the sphere and after some time we remove the wire that connected the 2 spheres.

What is the charge distribution of charge on the 2 spheres after we remove the potential? If we have charged the inner sphere instead, would the result be different?

## Homework Equations

Gauss's law

Electric field is the negative gradient of electrical potential

## The Attempt at a Solution

The answer provided was that the charge would all flow to the outer surface of the spherical shell, and the same would happen if we had placed Q on the inside of the conductor shell.

Now I'm trying to find an explanation to this.

At first I thought that because the electric field between R2 and R3 needs to be zero by Gauss law (we are inside a conductor), then the interior charge needs to be zero. Because of that all the charge will flow to the outside. But I don't think that makes sense because we could still have charge outside the inner sphere and on the inside surface of the shell if those charges would be on equilibrium...

Can someone please clarify me about this?

Also I don't understand what would happen if we didn't add charge Q to our system, would the result be different if we didn't add it?

Thanks!