How Does a Frictionless Incline Affect Crate Acceleration and Wheel Tension?

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SUMMARY

The discussion focuses on a physics problem involving a crate sliding down a frictionless incline and its interaction with a wheel. The crate, with a mass of 4.75 kg, accelerates at 2.4 m/s² down an incline of 25.0°. To find the tension in the cord (part a), participants are advised to apply Newton's second law, considering the forces acting on the crate. The rotational inertia of the wheel (part b) cannot be calculated directly using the formula I = MR² without knowing the mass of the wheel, as it is not specified whether the wheel is a uniform disk.

PREREQUISITES
  • Understanding of Newton's second law of motion
  • Familiarity with rotational inertia concepts
  • Knowledge of kinematic equations for acceleration
  • Basic principles of frictionless surfaces in physics
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  • Calculate the tension in the cord using Newton's second law
  • Determine the rotational inertia of the wheel once the tension is known
  • Explore the implications of frictionless surfaces on motion dynamics
  • Review the characteristics of different types of wheels and their inertia
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Students studying physics, particularly those focusing on mechanics, as well as educators seeking to clarify concepts related to forces and rotational motion.

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Homework Statement



A wheel of radius R = 30.0 cm is mounted on a frictionless horizontal axis. A massless cord is wrapped around the wheel and attached to a 4.75-kg crate that slides on a frictionless surface inclined at an angle of 25.0° with the horizontal. The crate accelerates down the incline at 2.4 m/s2.

(a) What is the tension in the cord?

(b) What is the rotational inertia of the wheel about its axis of rotation?

http://schubert.tmcc.edu/enc/66/4bc10f310fba6066d747ea495c942f9f2656106d7ddf2ff5d8b54e0cfacdd98a6596246f7119a41f9feaf3573da3a023248c9ec461bb2c9f6a44610f161f83989339c3411816f6076856c10d8af94242ce73cdf70aa0bc55.gif

Homework Equations



I = MR^2

I = Inertia
M = Mass
R = Radius


The Attempt at a Solution



I thought I could solve for part (b) using the above formula but I am not getting the correct answer. And I am not even sure how to start on part (a). Any help will be appreciated.
 
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CaptFormal said:
I thought I could solve for part (b) using the above formula but I am not getting the correct answer.
You're not given the mass, nor can you assume that the wheel is a uniform disk. So that won't work. First solve part (a), then use it to solve (b).
And I am not even sure how to start on part (a).
What forces act on the crate? Apply Newton's 2nd law.
 

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