Calculating Tension in a Cord Attached to an Inclined Crate

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Homework Help Overview

The discussion revolves around calculating the tension in a cord attached to a crate sliding down an inclined plane. The problem involves concepts from dynamics, specifically Newton's laws of motion, and the relationship between tension, mass, and acceleration.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the relationship between the crate's acceleration and the tension in the cord, with some questioning the relevance of the pulley’s mass. Others discuss the application of Newton's second law and the necessary equations to relate these variables.

Discussion Status

Participants are actively engaging with the problem, raising questions about the setup and the equations needed to find the tension. Some guidance has been offered regarding the use of Newton's second law, but there is no explicit consensus on the approach yet.

Contextual Notes

There is an assumption that the pulley is massless and frictionless, which may influence the calculations. The incline angle and the acceleration of the crate are provided, but further details on the system's dynamics are still being discussed.

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A wheel of radius R = 10.0 cm is mounted on a frictionless horizontal axis. A massless cord is wrapped around the wheel and attached to a 2.00-kg crate that slides on a frictionless surface inclined at an angle of 27.5° with the horizontal. The crate accelerates down the incline at 3.0 m/s2. What is the tension in the cord?

Is it possible to still work with this since there is no mass attached to the pulley? I'm pretty sure I need to use a moment of inertia equation to calculate the tension.
 
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Yes, you can do this without knowing the mass of the pulley.
 
How does this work? I'm having a few problems.
 
You've been given the acceleration of the crate. What's your equation relating the acceleration and tension of the crate (using Newton's second law)?
 
F=ma

Would I have to worry about the circle?
 
T=mg-ma

T=18.6*sin(27.5)-2*3
 
Last edited:

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