How Does the Rotational Inertia Affect Rolling Motion on an Inclined Plane?

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Homework Help Overview

The discussion revolves around the dynamics of a uniform wheel and axle system rolling down an inclined plane, focusing on the effects of rotational inertia on its motion. The problem involves calculating the rotational and translational kinetic energies of the system as it descends an incline of 30.0° after rolling a distance of 3.00 m.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the relationship between rotational and translational kinetic energy, questioning the role of the radius in the context of the wheel being partially in a groove. There is also confusion regarding the correct expression for rotational kinetic energy and the implications of the wheel's rotational inertia on its motion.

Discussion Status

Some participants have offered clarifications regarding the contact surfaces and the relationship between the wheel and axle's motion. There is an ongoing exploration of the assumptions about the system's dynamics, particularly concerning the effects of rotational inertia and the definition of the radius in the equations presented.

Contextual Notes

Participants are navigating the complexities of the problem setup, including the implications of the wheel being in a groove and the definitions of the variables involved in the kinetic energy equations. There is a noted correction regarding the terms used in the equations, indicating a need for precision in the discussion.

ILOVEPHYSIC
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A uniform wheel of mass 14.0 kg is mounted rigidly on a massless axle through its center, as shown in the figure below. The radius of the axle is 0.200 m, and the rotational inertia of the wheel-axle combination about its central axis is 0.600 kg·m2. The wheel is initially at rest at the top of a surface that is inclined at angle θ = 30.0° with the horizontal; the axle rests on the surface while the wheel extends into a groove in the surface without touching the surface. Once released, the axle rolls down along the surface smoothly and without slipping. The wheel-axle combination moves down the surface by 3.00 m.

(a)Determine its rotational kinetic energy at this point? J

(b) Determine its translational kinetic energy at this point? J

11-61.gif
Mgh= 1/2mw^2 + 1/2mv^2 --(1)
v=wR --(2)
The problem i feel confused is that what is R for since part of the wheel is inside the groove. I am not sure the question is just simply sub (2) into (1) and find the answer.
 
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ILOVEPHYSIC said:
Mgh= 1/2mw^2 + 1/2mv^2 --(1)
Fix the first term on the right hand side, for rotational KE. (Should be I, not m.)

ILOVEPHYSIC said:
The problem i feel confused is that what is R for since part of the wheel is inside the groove.
What matters is what surfaces are in contact with each other. It's the axle that is touching the surface of the incline. The fact that the part of the wheel is in the groove is irrelevant.
 
Doc Al said:
Fix the first term on the right hand side, for rotational KE. (Should be I, not m.)What matters is what surfaces are in contact with each other. It's the axle that is touching the surface of the incline. The fact that the part of the wheel is in the groove is irrelevant.
Sorry for typing wrong in rotational KE. But the axle and wheel should move with same angular speed. Why don't wheel slow down the rotational motion?
 
ILOVEPHYSIC said:
But the axle and wheel should move with same angular speed.
They do!

ILOVEPHYSIC said:
Why don't wheel slow down the rotational motion?
The wheel does slow down the rotational motion, but that is reflected in the rotational inertia. The relationship v = ωr is the condition for rolling without slipping; the "r" is the distance from the surface to the center, which is the radius of the axle, not the wheel.
 

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