Calculating Mass and Height Changes in a Hydraulic Lift

mattmannmf
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A hydraulic lift has two connected pistons with cross-sectional areas 5 cm2 and 650 cm2. It is filled with oil of density 720 kg/m3.

a) What mass must be placed on the small piston to support a car of mass 1400 kg at equal fluid levels?

10.77 OK

b) With the lift in balance with equal fluid levels, a person of mass 80 kg gets into the car. What is the equilibrium height difference in the fluid levels in the pistons?


c) How much did the height of the car drop when the person got in the car?

Now what i started off with was that pressure= mg/A (1480*9.8/ 650) and that equals density(g)(h)...so i got height change to be .003...but that's wrong
 
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so i figured out B..its 1.7

I just have no idea where to start for C
 

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