otterandseal1
- 16
- 0
- Homework Statement
- I'm struggling to get part b. I got part a to be (1,4,-1). Just got no clue for b. Pls help
- Relevant Equations
- Dont know what to put here
Can you find a normal to ##\pi_1##? You should be able to do this by inspection from its equation. Also, if two vectors are perpendicular, their dot product is 0.otterandseal1 said:Homework Statement:: I'm struggling to get part b. I got part a to be (1,4,-1). Just got no clue for b. Pls help
Relevant Equations:: Dont know what to put here
View attachment 259080
Is the normal (2,-1,-3)?Mark44 said:Can you find a normal to ##\pi_1##? You should be able to do this by inspection from its equation. Also, if two vectors are perpendicular, their dot product is 0.
is that using r.n = a.n ?ehild said:Yes.
You can find the normal of the other plane if you know two vectors the plane contains.
If ##\vec a## and ##\vec b## are vectors that lie in the plane you're trying to find the equation of, then ##\vec a \times \vec b## gives you a normal to that plane.otterandseal1 said:is that using r.n = a.n ?
Could you possibly show me the working for the question please?Mark44 said:If ##\vec a## and ##\vec b## are vectors that lie in the plane you're trying to find the equation of, then ##\vec a \times \vec b## gives you a normal to that plane.
No, can't do that, per the forum rules. See https://www.physicsforums.com/threads/physics-forums-global-guidelines.414380/, under Homework Guidelines.otterandseal1 said:Could you possibly show me the working for the question please?
Could I use the vector from part a? and the normal of the first plane?Mark44 said:No, can't do that, per the forum rules. See https://www.physicsforums.com/threads/physics-forums-global-guidelines.414380/, under Homework Guidelines.
Can you find two vectors in the plane you're trying to find?
If so, can you find their cross product? That will give you a normal to that plane. Once you have the normal, all you need is a single point in the plane, and you can find its equation.
Where the line meets the first planeehild said:What vector do you mean? And, yes. as the two planes are perpendicular the second plane contains the normal of the first plane.
No, it is a point , common point of the first plane an the line I. P (1,4,-1) is the position vector a of this point, it does not lie in the plane as vector b. But the line I lies in the second plane and so is its direction vector. What is it?otterandseal1 said:Where the line meets the first plane