How Does a Spring Scale Measure the Total Force in a Balanced Meter Ruler Setup?

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Homework Help Overview

The problem involves a uniform metre ruler suspended from a spring scale, with weights attached at specific points. The original poster questions the reading on the spring scale, considering the weights of both the apple and an additional weight, as well as the weight of the metre ruler itself.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the reading on the spring scale, with some suggesting it should include the weight of the metre ruler, while others question the clarity of the problem statement regarding the calibration of the scale.

Discussion Status

There is an ongoing exploration of the assumptions regarding the forces acting on the system. Some participants express doubts about the provided answer and suggest that the weight of the ruler should be considered in the calculation. Others propose that the scale may have been calibrated in a way that affects the reading.

Contextual Notes

Participants note that the ruler is in a stable position, neither moving nor rotating, which raises questions about how forces are balanced in this setup. The discussion reflects uncertainty about the implications of the ruler's weight on the spring scale's reading.

xiaomeizi
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Homework Statement


A uniform metre ruler of weight of 1.2N suspended at its mid-point from a spring scale which is calibrated in Newton(N).
An apple with weight of 0.75N, suspended from the metre rule at the 10cm mark, is balance by a weight of 1N, which is suspended from the 80cm mark. Assume g=10N/kg.
Q. what is the reading on the spring balance?

The reading on the spring balance= weight of both apple and the 100N. (0.75N+1N=1.75N)
I don't understand the answer. what about the weight of the metre ruler, balanced out by the upwards force ? I thought the spring scale is used to measure the tension, if that is the case, the tension should include the weight of the metre rule, isn't it ? could anyone dismiss my doubts? Thanks you. :D
 
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Homework Statement


A uniform metre ruler of weight of 1.2N suspended at its mid-point from a spring scale which is calibrated in Newton(N).
An apple with weight of 0.75N, suspended from the metre rule at the 10cm mark, is balance by a weight of 1N, which is suspended from the 80cm mark. Assume g=10N/kg.
Q. what is the reading on the spring balance?



Homework Equations





The Attempt at a Solution



The reading on the spring balance= weight downwards due to gravity
the answer suggested that (0.75N+1N=1.75N)
BUT, I don't understand the answer. what about the weight of the metre ruler, balanced out by the upwards force ? I thought the spring scale is used to measure the tension, if that is the case, the tension should include the weight of the metre rule, isn't it ? could anyone dismiss my doubts? Thanks you. :D
 
Yes, you are correct, the scale should read 2.95 N. Perhaps the scale was precalibrated to 0 with the meter stick alone on it? Like when you weigh a bunch of potatoes on a spring scale in a food store, the scale is adjusted to 0 with the pan weight alone on it, so you don't get overpriced. But the problem is not clear in that regard.
 


hi xiao

yes, the answer seems wrong. since the ruler is neither moving nor rotating, we have to use
the stability condition for the force. when we do that , the answer given seems wrong as it neglects the weight of the ruler...
 


IssacNewton said:
hi xiao

yes, the answer seems wrong. since the ruler is neither moving nor rotating, we have to use
the stability condition for the force. when we do that , the answer given seems wrong as it neglects the weight of the ruler...

Thanks for your reply.
 
(two threads merged)
 

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