How Does Acceleration Work in Reaching Maximum Speed?

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Homework Help Overview

The discussion revolves around understanding acceleration in the context of a car reaching its maximum speed. Participants are exploring the relationship between acceleration, time, and distance traveled as the car accelerates from rest to its maximum speed of 150 km/hr with a given acceleration rate of 5 km/hr².

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants are attempting to calculate the time required to reach maximum speed and the distance covered during acceleration. Questions arise regarding the interpretation of average speed and the calculation of distance over time.

Discussion Status

There is ongoing exploration of the calculations related to distance and speed. Some participants are questioning the accuracy of the distance calculations and the assumptions made about average speed over time. Guidance has been offered regarding the need to calculate distance for each hour of acceleration rather than using average speeds directly.

Contextual Notes

Participants are discussing the implications of using average speed versus instantaneous speed in their calculations. There is also a mention of splitting off part of the discussion into a separate thread for clarity.

Raza
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Okay, Can someone do these for me so I can understand acceleration:

My car can reach a maximum speed of 150km/hr. And my car can acclerate at 5km/hr2. How long will it take for my car to reach 150km/hr from rest.
I know acceleration is the velocity of the velocity and the eqn for acceleration but I don't know how it works.
 
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Raza said:
My car can reach a maximum speed of 150km/hr. And my car can acclerate at 5km/hr2. How long will it take for my car to reach 150km/hr from rest.
From the definition of acceleration as the rate of change of velocity, the average acceleration will equal the change in velocity divided by the time:
a = (Vf - Vi)/t or Vf = Vi + at

Plugging in your values and solving for time gives: t = 30 hr.
 
So in 1 hour, it went from 0km/hr to 5km/hr. And in the 2nd, it went to 10km\hr. In 5 hours, how much distance did it cover?
 
At the end of 5 hours, its speed will be 25 km/hr. During those 5 hours the average speed, since it started from rest, is 12.5 km/hr. Use that speed to calculate the distance: 62.5 km.
 
1hr=5km/hr
2hr=10km/hr
3hr=15km/hr
4hr=20km/hr
5hr=25km/hr
5+10+15+20+25=75
75/5=15km\hr
at the end of 5hr, it will be 15km\hr x 5hr, which is 75km.
Why is the answer 62.5km?
 
Raza said:
1hr=5km/hr
2hr=10km/hr
3hr=15km/hr
4hr=20km/hr
5hr=25km/hr
These are the speeds at those times. So?
5+10+15+20+25=75
What's this supposed to represent? Not the distance travel in each hour, I hope.

If that's what you're doing, start by working out the distance traveled in the first hour. Hint: It's not 5 km.

(I'm going to split off this discussion into a separate thread in "Intro Phys".)
 

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