How Does Adding Nitrogen Affect Pressure in a Sealed Tank?

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Homework Help Overview

The discussion revolves around a problem involving a sealed storage tank containing nitrogen gas at standard temperature and pressure (STP). The original poster seeks to determine the volume of the tank and the pressure after adding additional nitrogen without changing the temperature.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to calculate the number of moles of nitrogen and the corresponding volume of the tank. They also explore the pressure change after adding more nitrogen, questioning the assumption that volume remains constant. Other participants suggest checking calculations and performing dimensional analysis to clarify discrepancies in pressure units.

Discussion Status

Participants are actively engaging with the problem, offering guidance on checking calculations and emphasizing the relationship between pressure and the number of moles in the context of the ideal gas law. There is an ongoing exploration of the assumptions made regarding volume and temperature.

Contextual Notes

There is a noted confusion regarding unit conversions and the implications of holding volume constant while adding gas. The original poster's calculations are scrutinized for potential errors in dimensional analysis.

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Homework Statement

[/b][/B]


a Storage tank at STP contains 18,5kg of nitrogen (N2). a) What is the volume of the tank? b) What is the pressure if an additional 15.kg of nitrogen is added without changing the temperature.


Homework Equations


n= m/molar mass
P= nRT/V

The Attempt at a Solution



For a) I got n= m/molar mass --> 18.5 X 1000 / 28 = 660.71 mol
1 mole occupies 22.4 L
--> V= 660.71 X 22.4 = 14 799.99 L 14.8 m^3

For b) I have T= 273.15 n= (18.5 +15) x 1000 /28= 1196 mol
i think for some reason V is assumed to be constant and doesn't change so ,
--> P= nRT/V, which gives me 183.44 N/m^2

However in b the answerr is suppose to be 1.83 X10^5 Pa, or 183 X 10^ 3 Pa, ans I thought n/m^2 is the same units as Pa. I would like clarification, thanks
 
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Myr73 said:
For b) I have T= 273.15 n= (18.5 +15) x 1000 /28= 1196 mol
i think for some reason V is assumed to be constant and doesn't change so ,
--> P= nRT/V, which gives me 183.44 N/m^2
"for some reason"??
Don't you know?!
i.e. does the tank change size?

However in b the answerr is suppose to be 1.83 X10^5 Pa, or 183 X 10^ 3 Pa, ans I thought n/m^2 is the same units as Pa. I would like clarification, thanks
So you are out by a factor of 1000?

Take a closer look at your numbers. Do a dimensional analysis to check the units.
i.e. show me the exact calculation - you missed a term or divided by 1000 when you shouldn;t have or forgot an exponent.

Note: the calculation is easier is you compare the state equations before and after the extra mass is added.
 
Oh I see, I should have used V in m^3 not in L. Thank you
 
Regarding Part b: From the ideal gas law, if the temperature and volume are held constant, the pressure is proportional to the number of moles.

Chet
 
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