How Does an Electron Impact the Walls of an Infinite Potential Well?

Click For Summary
SUMMARY

An electron confined to an infinite potential well of width L exerts a force on the walls that can be estimated using the uncertainty principle and calculated using the ground-state wavefunction. The uncertainty principle states that \(\Delta x \cdot \Delta p \geq \frac{\hbar}{2}\), leading to the estimation of force as \(F = \frac{dp}{dt} = \frac{mc^2}{L}\). The ground state corresponds to \(n=1\), and the normalization of the wavefunction for a superposition of states requires careful integration, resulting in the normalization constant \(A = \sqrt{\frac{2}{L}}\) for a single eigenstate, adjusted for superpositions.

PREREQUISITES
  • Quantum Mechanics fundamentals, specifically the concept of potential wells
  • Understanding of the uncertainty principle in quantum mechanics
  • Familiarity with Schrödinger's equation for one-dimensional systems
  • Knowledge of wavefunction normalization techniques
NEXT STEPS
  • Study the derivation of forces in quantum systems using the uncertainty principle
  • Learn about the ground-state wavefunction for infinite potential wells
  • Explore normalization of wavefunctions in quantum mechanics
  • Investigate the implications of superposition in quantum states
USEFUL FOR

Students and professionals in physics, particularly those focusing on quantum mechanics, wavefunctions, and potential wells, will benefit from this discussion.

laxatives
Messages
5
Reaction score
1

Homework Statement



An electron is confined to an infinite potential well of width L. Find the force it exerts on the walls of the well in the lowest energy state:
a) Estimate the force using uncertainty principle
b) Calculate the force exactly for the ground-state wavefunction

Homework Equations


[tex]\Delta[/tex]x = L
[tex]\Delta[/tex]x * [tex]\Delta[/tex]p [tex]\geq[/tex] [tex]\frac{hbar}{2}[/tex]
[tex]\Delta[/tex]E * [tex]\Delta[/tex]t = [tex]\frac{hbar}{2}[/tex]

The Attempt at a Solution


I used the uncertainty principle to solve for [tex]\Delta[/tex]p and [tex]\Delta[/tex]t and divided to get F=dp/dt = (mc^2)/L. I'm not sure if this is correct. I actually didn't really have much of a start until I started typing this up just now.

For part b: I'm not sure what the ground-state wavefunction is. Does this mean k = 1?
I have Schrödinger's equation for 1D, the Hamiltonian, and Hermite polynomials, but don't really know where to begin to relate it all back to force.Another question:

Homework Statement



Normalize the wavefunction u(x) proportional to sin(pi*x/L) + sin(2pi*x/L) for a particle of mass m bound in an infinitely deep one-dimensional potential well extending from x = 0 to x = L.

Homework Equations



1 = A^2 Integral u(x)^2 dx

The Attempt at a Solution



So I want to solve for A by integrating the u(x)^2 dx from 0 to L since the probability of finding the particle outside of the well is zero. I found a solution online that states A = (2/L)^(1/2) but I keep calculating the integral to be L resulting in A = (1/L)^(1/2). What am I missing?
 
Last edited:
  • Like
Likes   Reactions: Niraj Shah
Physics news on Phys.org
laxatives said:

Homework Statement



An electron is confined to an infinite potential well of width L. Find the force it exerts on the walls of the well in the lowest energy state:
a) Estimate the force using uncertainty principle
b) Calculate the force exactly for the ground-state wavefunction

Homework Equations


[tex]\Delta[/tex]x = L
[tex]\Delta[/tex]x * [tex]\Delta[/tex]p [tex]\geq[/tex] [tex]\frac{\hbar}{2}[/tex]
[tex]\Delta[/tex]E * [tex]\Delta[/tex]t = [tex]\frac{\hbar}{2}[/tex]

The Attempt at a Solution


I used the uncertainty principle to solve for [tex]\Delta[/tex]p and [tex]\Delta[/tex]t and divided to get F=dp/dt = (mc^2)/L. I'm not sure if this is correct. I actually didn't really have much of a start until I started typing this up just now.
The uncertainty principle relating energy and time doesn't apply here. You want to estimate the time from the width of the well and the momentum of the electron.
For part b: I'm not sure what the ground-state wavefunction is. Does this mean k = 1?
I have Schrödinger's equation for 1D, the Hamiltonian, and Hermite polynomials, but don't really know where to begin to relate it all back to force.
The ground state is the lowest-energy state. I'm not sure what conventions you're using, but usually, the ground state corresponds to n=1; k is typically the spatial frequency 2π/λ.

The Hermite polynomials have nothing to do with this problem. They appear in the solutions for the quantum mechanical simple harmonic oscillator.

From the wording of the question, I'm not sure what they had in mind. I would calculate the force by considering what happens to the energy if the width of the well were increased by an infinitesimal amount.
Another question:

Homework Statement



Normalize the wavefunction u(x) proportional to sin(pi*x/L) + sin(2pi*x/L) for a particle of mass m bound in an infinitely deep one-dimensional potential well extending from x = 0 to x = L.

Homework Equations



1 = A^2 Integral u(x)^2 dx

The Attempt at a Solution



So I want to solve for A by integrating the u(x)^2 dx from 0 to L since the probability of finding the particle outside of the well is zero. I found a solution online that states A = (2/L)^(1/2) but I keep calculating the integral to be L resulting in A = (1/L)^(1/2). What am I missing?
Your answer is correct. The factor sqrt(2/L) is for a single eigenstate. You have a superposition of two eigenstates, so the factor is reduced by 1/sqrt(2).
 

Similar threads

Replies
27
Views
3K
Replies
30
Views
5K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
18
Views
4K
  • · Replies 7 ·
Replies
7
Views
3K
Replies
28
Views
2K
Replies
64
Views
6K
Replies
5
Views
1K
Replies
1
Views
2K