A How Does Anisotropy Affect the Calculation of Taylor Microscale in Turbulence?

Click For Summary
The Taylor microscale can be calculated for anisotropic turbulence using the modified equation that accounts for anisotropic velocity fluctuations. In cases where two velocity components are zero, the expression simplifies to λ_A = √(5ν/ε)√(v'_1²). This approach remains valid as the anisotropy affects only the magnitude of the fluctuations, not the overall formula. References for further reading include "Anisotropic Turbulence" and "Turbulence: An Introduction for Scientists and Engineers." Understanding these concepts is crucial for accurately analyzing turbulence in various applications.
rdemyan
Messages
67
Reaction score
4
TL;DR
Anisotropic Taylor microscale
The Taylor microscale in isotropic turbulence is given by:
$$\lambda = \sqrt{ 15 \frac{\nu \ v'^2}{\epsilon} }$$

where v' is the root mean square of the velocity fluctuations. In general, for velocity fluctuations in three dimensions:

$$v' = \frac{1}{\sqrt{3}}\sqrt{{v'_1}^2+{v'_2}^2+{v'_3}^2}$$

So plugging this expression into the Taylor microscale equation yields:
$$\lambda = \sqrt{ 5 \frac{\nu}{\epsilon} }\sqrt{{v'_1}^2+{v'_2}^2+{v'_3}^2}$$

Now for isotropic turbulence

$$v'_1=v'_2=v'_3$$

So for isotropic turbulence, equation 3 (third equation in this text) yields:

$$\lambda = \sqrt{ 5 \frac{\nu}{\epsilon} }\sqrt{{3v'_1}^2} = \sqrt{ 15 \frac{\nu \ {v'_1}^2}{\epsilon} }$$

My question is: can I use equation 3 to calculate the Taylor microscale for anisotropic turbulence. For example if the injection of energy is highly anisotropic where ##v'_2 = v'_3=0##

$$\lambda_A = \sqrt{ 5 \frac{\nu}{\epsilon} }\sqrt{{v'_1}^2}=\sqrt{ 5 \frac{\nu \ {v'_1}^2}{\epsilon} }$$

where ##λ_A## is the anisotropic Taylor microscale. Does this seem correct? Also, does anyone know of a reference where this derivation was already done?
 
Last edited:
Physics news on Phys.org


Yes, you can use equation 3 to calculate the Taylor microscale for anisotropic turbulence as long as you take into account the anisotropy in the velocity fluctuations. In your example, where ##v'_2 = v'_3=0##, the Taylor microscale would be given by:

$$\lambda_A = \sqrt{ 5 \frac{\nu}{\epsilon} }\sqrt{{v'_1}^2+0+0}=\sqrt{ 5 \frac{\nu \ {v'_1}^2}{\epsilon} }$$

This is because the anisotropy in the velocity fluctuations only affects the magnitude of the velocity fluctuations, not the overall expression for the Taylor microscale.

As for references, there are many papers and textbooks that discuss the anisotropic Taylor microscale, such as "Anisotropic Turbulence" by F. Anselmet, Y. Gagne, E. J. Hopfinger, and R. A. Antonia, and "Turbulence: An Introduction for Scientists and Engineers" by P. A. Davidson. You can also find many research papers that use this equation to calculate the anisotropic Taylor microscale in various types of turbulence.
 
Thread 'Why higher speeds need more power if the backward force is the same?'
Power = Force v Speed Power of my horse = 104kgx9.81m/s^2 x 0.732m/s = 1HP =746W Force/tension in rope stay the same if horse run at 0.73m/s or at 15m/s, so why then horse need to be more powerfull to pull at higher speed even if backward force at him(rope tension) stay the same? I understand that if I increase weight, it is hrader for horse to pull at higher speed because now is backward force increased, but don't understand why is harder to pull at higher speed if weight(backward force)...

Similar threads

Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 30 ·
2
Replies
30
Views
2K
  • · Replies 20 ·
Replies
20
Views
3K
Replies
1
Views
381
  • · Replies 16 ·
Replies
16
Views
3K
Replies
4
Views
2K
  • · Replies 25 ·
Replies
25
Views
2K
Replies
19
Views
2K
Replies
1
Views
1K