How Does Avogadro's Number Impact Molar Mass Calculations?

[mystmyst]

Homework Statement

I only have a question on the calculation, so I won't even give the question...
My book says

$$(0.5877 \times 10^{-23} \:g) \times (6.022 \times 10^{-23} \: mol^{-1} )= 35.45 \: g \cdot mol^{-1}$$


According to my calculator $$(0.5877 \times 10^{-23} \:g) \times (6.022 \times 10^{-23} \: mol^{-1})= 3.545 \times 10^{-46} \: g \cdot mol^{-1}$$

How did they get rid of the $$10^{-46}$$ sign??

Thanks!

 

[Borek]

There is an error in the expression, should be 6.022x10²³, not 6.022x10^-23. This is the Avogadro's number.

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