How Does Bath Oil Depth Affect Soap Buoyancy?

[apchemstudent]

This is what i have:

Fbw=mg
dw*vw*g=ds*vs*g
density of soap=717.7

Fbo + Fbw2 = mg
(0.639*XA*9.81) + (100*YA*9.81) = d*v*g
cancel terms and you get
(0.639*X) + (1000*Y) = d

i know you relate them through thickness of the soap but how?

The volume has not been divided out completely. Reread OldDan's previous posts more carefully, about drawing out the soap... X and Y are the heights of the soap subermerged in each liquid... just read the previous posts more carefully

 

[DDS]

I know i made a mistake in righting it, its supposed to be:

(0.639*X) + (1000*Y) = ds * 0.0209


then form here is used my two equaions to find x and y but i seem to be getting the answer from which i originally thaught it would be:


i know x+y =0.0209 m

and i also know that

x=23.45 - 1564.9y
which i got from simplyfiying the very first equation in this post.


from there i found that

Y= 0.0149m
and X=5.91e-3

then wouldn't the depth of the oil layer be equal to my value from X or am i missing something??

 

[apchemstudent]

I know i made a mistake in righting it, its supposed to be:

(0.639*X) + (1000*Y) = ds * 0.0209


then form here is used my two equaions to find x and y but i seem to be getting the answer from which i originally thaught it would be:


i know x+y =0.0209 m

and i also know that

x=23.45 - 1564.9y
which i got from simplyfiying the very first equation in this post.


from there i found that

Y= 0.0149m
and X=5.91e-3

then wouldn't the depth of the oil layer be equal to my value from X or am i missing something??

the density of oil is not 0.639.

 

[DDS]

of course its not i negelcted to convert specific gravity to density

i got the answer