How Does Calculus Explain How V=S/T & DV=DS/DT?

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SUMMARY

The discussion clarifies the distinction between average velocity (v = s/t) and instantaneous velocity (dv = ds/dt). While v = s/t represents the average velocity over a time interval, dv = ds/dt accurately describes the instantaneous velocity at a specific moment. The conversation references Galileo's equations, specifically v = u + at and s = ut + 1/2at², emphasizing that calculus allows for the analysis of instantaneous changes rather than mere averages. The importance of differentiating between average and instantaneous rates of change is underscored, with a focus on the role of calculus in understanding these concepts.

PREREQUISITES
  • Understanding of basic calculus concepts, particularly differentiation.
  • Familiarity with kinematic equations, specifically Galileo's equations.
  • Knowledge of the distinction between average and instantaneous rates of change.
  • Basic understanding of limits and their application in calculus.
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  • Study the principles of differentiation in calculus, focusing on instantaneous rates of change.
  • Explore the application of limits in calculus to understand how they relate to instantaneous velocity.
  • Review the historical context and contributions of the Oxford Calculators to the development of calculus.
  • Investigate the relationship between acceleration and velocity through the equation dv/dt = a.
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Students of physics and mathematics, educators teaching calculus concepts, and anyone interested in the foundational principles of motion and acceleration in classical mechanics.

abrahamjp
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Dear Sirs,

I am wondering what is the difference between v=s/t & dv = ds/dt where v-velocity,s-displacement,t-time.

Consider Gallelio's equations->
v=u+at--(equation-1) &
s=ut+1/2at^2--(equation-2)
where u-initial velocity & a-acceleration

My doubt is on following point;

If we do,v = s/t in equation-2,we get->v=u+1/2at not v=u+at
but if we do,dv=ds/dt in equation-2,we get=>v=u+at ,exactly the equation we want.

why only differentiation give the result,not just mere divison?
 
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v=s/t is the AVERAGE velocity over the total time INTERVAL "t".
Thus, it does NOT give the velocity at the INSTANT "t"
 
abrahamjp said:
I am wondering what is the difference between v=s/t & dv = ds/dt where v-velocity,s-displacement,t-time.

Hi !
dv = ds/dt has no meaning at all !
dv is an infinitesimal value (a very small variation of v). Do not confuse it with v.
ds is a small displacement during dt a small variation of time.
So, ds/dt is the speed at time t, which is not infinitesimal, hense not equal to dv.
Do not confuse the average speed s/t with the instantaneous speed ds/dt. Use two different symbols, not v for both.
dt is the small variation of speed during a small variation of time. So, dv/dt is the acceleration.
 
Last edited:
dv/dt is at an instantaneous time... Not division.
 
iRaid said:
dv/dt is at an instantaneous time... Not division.
It's the acceleration at an arbitrary time.
 
Galileo's equations work only for constant accelerations; the theory was worked out by the "Oxford Calculators":
http://en.wikipedia.org/wiki/Oxford_Calculators

Galilleo's experiments showed that gravity was constant (at the surface of the earth), and was thus able to apply these equations.

Calculus allows you to work with arbitrary accelerations; instead of working with algebraic averages it makes use of limits. Between the time of Galileo and Newton, Rene Descartes invented analytic geometry ... this is the tool required to move from the geometric analysis of Galileo to the calculus of Newton and Leibniz.
 
equation v=u+at is merely rearranged from the average acceleration formula \displaystyle\frac{v-u}{t}=a.

In calculus we get the instantaneous versions of these, \displaystyle\frac{dv}{dt} = a, and v(t)=\displaystyle\int a(t) dt
 

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