How Does Centripetal Acceleration Affect an Astronaut's Motion in a Centrifuge?

Click For Summary

Homework Help Overview

The discussion revolves around a physics problem involving centripetal acceleration experienced by an astronaut in a centrifuge. The specific queries include calculating the astronaut's speed, the required revolutions per minute, and the period of motion, given a centripetal acceleration of 8.0g at a radius of 3.0 m.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss the application of the centripetal acceleration formula and its rearrangement to find velocity. There are questions about the conversion between frequency and revolutions per minute, as well as concerns regarding significant figures in the calculations.

Discussion Status

Some participants have identified issues with unit conversions and significant figures, while others are exploring the implications of these factors on their calculations. There is an ongoing examination of the relationships between velocity, frequency, and period, but no consensus has been reached.

Contextual Notes

Participants note that the problem may have specific requirements regarding significant figures that could affect their answers. There is also a distinction being made between RPM and frequency, which is under discussion.

mbrmbrg
Messages
486
Reaction score
2
An astronaut is rotated in a horizontal centrifuge at a radius of 3.0 m.
(a) What is the astronaut's speed if the centripetal acceleration is 8.0g?
(b) How many revolutions per minute are required to produce this acceleration?
(c) What is the period of the motion?

I got the question all wrong, all wrong... la-la la... ROAR!

for part a) I used the equation a=\frac{v^2}{r} which rearranges into v= \sqrt{ar}. Plug in my values and get v=\sqrt{(8.0)(9.81m/s^2)(3.0m)}=15.34

This gets used for parts b and c, which is why I'd get those wrong, too...

What I did for part c) is T= \frac{2\pi r}{v} = \frac{6\pi}{15.34} = 0.81.

And part b) asks for frequency, which is 1/T so I plugged in for f=\frac{v}{2\pi\r}
 
Last edited:
Physics news on Phys.org
RPM is not frequency.
 
Right, the units don't line up. Oops. Is frequency rev/sec, though? So to get from frequency to rev/min, multiply frequency by 60s/min?

But I still don't know why my velocity is off, so I can't get the right answer anyway.
 
OK, got it. the problem with velocity is that WebAssign wanted 3 figures even though sig-figs only required 2.
 

Similar threads

Replies
55
Views
3K
Replies
16
Views
959
Replies
11
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 28 ·
Replies
28
Views
3K
Replies
2
Views
2K
  • · Replies 14 ·
Replies
14
Views
5K
Replies
14
Views
2K
  • · Replies 17 ·
Replies
17
Views
9K
  • · Replies 9 ·
Replies
9
Views
2K