How Does Changing Temperature and Pressure Affect Gas Density?

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SUMMARY

The discussion focuses on calculating the density of nitrogen gas under varying temperature and pressure conditions using the ideal gas law. Given the initial conditions of 273 K and 1.013 x 105 Pa, the density is 1.25 kg/m3. When the temperature is increased to 330 K and the pressure to 1.40 x 105 Pa, the resulting density is calculated to be 1.43 kg/m3, confirming the relationship between gas density, temperature, and pressure.

PREREQUISITES
  • Understanding of the ideal gas law (pV = nRT)
  • Knowledge of gas density calculations
  • Familiarity with temperature and pressure units (Kelvin and Pascal)
  • Basic algebra for manipulating equations
NEXT STEPS
  • Study the ideal gas law and its applications in real-world scenarios
  • Learn about the effects of temperature and pressure on gas behavior
  • Explore advanced gas laws, such as Van der Waals equation
  • Investigate the concept of molar volume and its implications in gas density
USEFUL FOR

Students in physics and chemistry, educators teaching gas laws, and professionals in fields requiring gas density calculations, such as engineering and environmental science.

annalian
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Homework Statement


In temperature 273 kelvin and pressure 1.013*10^5 Pa, the density of nitrogen is 1,25 kg/m3. Find the density of this gas in temperature 330 kelvin and pressure 1.40*10^5 Pa.

T1=273 K; p1=1.013*10^5Pa; d1=1.25 kg/m3

T2=330 K; p2 =1.4*10^5 Pa. d2=?

Homework Equations


p1V1/T1=p2V2/T2

The Attempt at a Solution


https://image.ibb.co/bxkPAa/phys.png
phys.png

d2=1.43 kg/m^3
 
Last edited:
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Looks good. What's your final result?
 
gneill said:
Looks good. What's your final result?
d2=1.43 kg/m^3
 
annalian said:
d2=1.43 kg/m^3
Good!
 

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